Php mysql和按日期加入组

你好，我需要帮助来解决我的代码在这里

我尝试了以下查询

SELECT DATE_FORMAT(buy.date, '%Y-%m-%d') date 
     , SUM(buy.total) sumbuy 
     , SUM(sell.total) sumsell  
  FROM buy  
  JOIN sell  
    ON DATE_FORMAT(buy.date, '%Y-%m-%d') = DATE_FORMAT(sell.date,'%Y-%m-%d') 
 WHERE buy.trans = 'credit' 
   AND sell.trans= 'debit'  
 GROUP 
    BY DATE_FORMAT(buy.date, '%d')

结果是：

   date        sumbuy       sumsell
 ------------------------------------
 2017-02-01    1560000      8080000

我所期望的是：

        date        sumbuy       sumsell
     ------------------------------------
     2017-02-01     390000       2020000

这是完整的桌子

买

出售

---

请任何人帮我解决这个问题。

“没有办法把它变成一张桌子”——坦率地说，这个断言是荒谬的

无论如何

DROP TABLE IF EXISTS buy;

CREATE TABLE buy
(total INT NOT NULL
,trans enum('credit','debit')
,date DATETIME NOT NULL);

INSERT INTO buy VALUES
(140000,'credit','2017-02-01 04:31:00'),
( 50000,'credit','2017-02-01 04:32:00'),
(190000,'debit' ,'2017-02-01 04:33:00'),
( 50000,'credit','2017-02-01 04:34:00'),
(150000,'credit','2017-02-01 04:35:00');

DROP TABLE IF EXISTS sell;

CREATE TABLE sell
(total INT NOT NULL
,trans enum('credit','debit')
,date DATETIME NOT NULL);

INSERT INTO sell VALUES
(120000,'debit','2017-02-01 04:31:00'),
(300000,'debit','2017-02-01 04:32:00'),
(800000,'debit','2017-02-01 04:33:00'),
(800000,'debit','2017-02-01 04:35:00');

SELECT DATE(date) date 
     , SUM(CASE WHEN type = 'buy' AND trans = 'credit' THEN total END) sumbuy
     , SUM(CASE WHEN type = 'sell' AND trans = 'debit' THEN total END) sumsell 
  FROM
     ( SELECT * 
            ,'buy' type 
         FROM buy
        UNION 
          ALL
       SELECT *
            ,'sell' 
         FROM sell
     ) x
 GROUP 
    BY DATE(date);
+------------+--------+---------+
| date       | sumbuy | sumsell |
+------------+--------+---------+
| 2017-02-01 | 390000 | 2020000 |
+------------+--------+---------+
1 row in set (0.02 sec)

---

您的问题已经有了解决方案，但也许这一方案可以在其他情况下帮助其他人

select date, sum(sumbuy) as totalbuy, sum(sumsell) as totalsell from (SELECT DATE_FORMAT(buy.date, '%Y-%m-%d') date 
     , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
     , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
  FROM buy 
  GROUP 
    BY DATE_FORMAT(buy.date, '%d')
union 
SELECT DATE_FORMAT(sell.date, '%Y-%m-%d') date 
     , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
     , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
  FROM sell 
  GROUP 
    BY DATE_FORMAT(sell.date, '%d')) a
    group by date

我注意到您在sumsell中获得了2020000，不应该是221000，或者您明确不希望从buy表中获得借记交易

如果您只需要sell表中的借项，而只需要buy表中的贷项，您可以像这样重写查询：

select date, sum(sumbuy) as totalbuy, sum(sumsell) as totalsell from (SELECT DATE_FORMAT(buy.date, '%Y-%m-%d') date 
 , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
 , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
  FROM buy 
 where trans = 'credit'
GROUP 
BY DATE_FORMAT(buy.date, '%d')
union 
SELECT DATE_FORMAT(sell.date, '%Y-%m-%d') date 
 , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
 , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
FROM sell 
where trans = 'debit'
GROUP 
BY DATE_FORMAT(sell.date, '%d')) a
group by date

---

对于我来说，有一个买入表和卖出表，以及一个可以是借方和贷方的trans列，这似乎让我感到困惑。看，我很困惑。为什么不只有一个表呢？我的项目需要两个表，这是一个例子，所以我很简单，：dw为什么需要两个表？你可以按类型推迟交易。因为两个表都有借记和贷记交易，无法成为一个表140000+50000+50000+150000=390000和@草莓再次击败我，仍然在努力寻找更好的解决方案，也许我需要将我的尼克改为？嗯，非常有用的答案。非常感谢你，草莓。@草莓，在这种情况下只有几条记录，但是在许多记录的情况下，哪种解决方案工作得更快？@davejal我怀疑其中没有太多内容，但如果不进行测试，我就不知道了。

select date, sum(sumbuy) as totalbuy, sum(sumsell) as totalsell from (SELECT DATE_FORMAT(buy.date, '%Y-%m-%d') date 
     , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
     , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
  FROM buy 
  GROUP 
    BY DATE_FORMAT(buy.date, '%d')
union 
SELECT DATE_FORMAT(sell.date, '%Y-%m-%d') date 
     , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
     , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
  FROM sell 
  GROUP 
    BY DATE_FORMAT(sell.date, '%d')) a
    group by date

select date, sum(sumbuy) as totalbuy, sum(sumsell) as totalsell from (SELECT DATE_FORMAT(buy.date, '%Y-%m-%d') date 
 , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
 , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
  FROM buy 
 where trans = 'credit'
GROUP 
BY DATE_FORMAT(buy.date, '%d')
union 
SELECT DATE_FORMAT(sell.date, '%Y-%m-%d') date 
 , SUM(case when trans = 'credit' then total else 0 end) as sumbuy
 , SUM(case when trans = 'debit' then total else 0 end) as sumsell 
FROM sell 
where trans = 'debit'
GROUP 
BY DATE_FORMAT(sell.date, '%d')) a
group by date