Php 将正则表达式更改为不包含[and]中的内容

我这里有一个自动链接的正则表达式代码：

// turn any url into url bbcode that doesn't have it already - so we can auto link urls- thanks stackoverflow

$URLRegex = '/(?:(?<!(\[\/url\]|\[\/url=))(\s|^))'; // No [url]-tag in front and is start of string, or has whitespace in front
$URLRegex.= '(';                                    // Start capturing URL
$URLRegex.= '(https?|ftps?|ircs?):\/\/';            // Protocol
$URLRegex.= '\S+';                                  // Any non-space character
$URLRegex.= ')';                                    // Stop capturing URL
$URLRegex.= '(?:(?<![.,;!?:\"\'()-])(\/|\s|\.?$))/i';      // Doesn't end with punctuation and is end of string, or has whitespace after

$body = preg_replace($URLRegex,"$2[url=$3]$3[/url]$5", $body);

正确的输出是：

<div class="quote"><strong>Quote from liamdawe</strong><br />  Have you had a look at <a href="http://pcgamingwiki.com/wiki/Serious_Sam_II#Linux_Installation" target="_blank">this howto</a>? <img src="/jscripts/sce/emoticons/smile.png" alt="" /><br />
<br />
<a href="http://pcgamingwiki.com/wiki/Serious_Sam_II#Linux_Installation" target="_blank">http://pcgamingwiki.com/wiki/Serious_Sam_II#Linux_Installation</a></div><br />
Testing

引用liamdawe
你看过吗





测试

但我得到的结果是：

<div class="quote"><strong>Quote from liamdawe</strong><br />  Have you had a look at <a href="http://pcgamingwiki.com/wiki/Serious_Sam_II#Linux_Installation" target="_blank">this howto</a>? <img src="/jscripts/sce/emoticons/smile.png" alt="" /><br />
<br />
<a href="http://pcgamingwiki.com/wiki/Serious_Sam_II#Linux_Installation </div>" target="_blank">http://pcgamingwiki.com/wiki/Serious_Sam_II#Linux_Installation[/quote]</a><br />
Testing<br />

引用liamdawe
你看过吗





测试

正如您所见，它在链接中包含了[/quote]标记，因为它没有忽略自动链接器regex中的bbcode标记

如果需要，下面是执行该类型报价的代码： //引用真实的人、书或任何东西 $pattern='/[quote\=（.+？）]（.+？）[/quote]/is'

$replace = "<div class=\"quote\"><strong>Quote from $1</strong><br />$2</div>";

while(preg_match($pattern, $body))
{
    $body = preg_replace($pattern, $replace, $body);
}

$replace=“引用$1
$2”；
while（preg_match（$pattern，$body））
{
$body=preg_replace（$pattern，$replace，$body）；
}

试试这个

$URLRegex = '/(?:(?<!(\[\/url\]|\[\/url=))(\s|^))'; // No [url]-tag in front and is start of string, or has whitespace in front
$URLRegex.= '(';                                    // Start capturing URL
$URLRegex.= '(https?|ftps?|ircs?):\/\/';            // Protocol
$URLRegex.= '[\w\d\.\/#\_\-\?:=]+';                        // Any non-space character
$URLRegex.= ')';                                    // Stop capturing URL
$URLRegex.= '(?:(?<![.,;!?:\"\'()-])(\/|\[|\s|\.?$))/i';      // Doesn't end with punctuation and is end of string, or has whitespace after

$body = preg_replace($URLRegex,"$2[url=$3]$3[/url]$5", $body);

---

$URLRegex='/（？：（？请给我们显示前后的代码。这是不相关的。这是做链接的所有代码。那么给你任何帮助都不相关。你能给我们一个示例输入、当前输出和所需输出吗？添加了示例，添加了引号代码，以显示它是如何完成的（如果需要）。
$URLRegex = '/(?:(?<!(\[\/url\]|\[\/url=))(\s|^))'; // No [url]-tag in front and is start of string, or has whitespace in front
$URLRegex.= '(';                                    // Start capturing URL
$URLRegex.= '(https?|ftps?|ircs?):\/\/';            // Protocol
$URLRegex.= '[\w\d\.\/#\_\-\?:=]+';                        // Any non-space character
$URLRegex.= ')';                                    // Stop capturing URL
$URLRegex.= '(?:(?<![.,;!?:\"\'()-])(\/|\[|\s|\.?$))/i';      // Doesn't end with punctuation and is end of string, or has whitespace after

$body = preg_replace($URLRegex,"$2[url=$3]$3[/url]$5", $body);