Php Laravel SQL groupBy和Sum
这是我的表格关系:Php Laravel SQL groupBy和Sum,php,mysql,laravel,laravel-5,Php,Mysql,Laravel,Laravel 5,这是我的表格关系: **reservations** id, date, etc...<br> **reservation_service_info** service_info_id, reservation_id<br> **services_info** price etc... 结果: [ { "date": "2016-06-01", "price": "345.00" }, { "date": "2016-06-01",
**reservations** id, date, etc...<br>
**reservation_service_info** service_info_id, reservation_id<br>
**services_info** price etc...
结果:
[
{
"date": "2016-06-01",
"price": "345.00"
},
{
"date": "2016-06-01",
"price": "90.00"
},
{
"date": "2016-06-01",
"price": "222.00"
},
{
"date": "2016-06-02",
"price": "393.00"
},
{
"date": "2016-06-02",
"price": "142.00"
}
]
当我在查询中添加groupBy('date')
时,它会根据dosent SUM(价格)对其进行分组
您应该使用sum(price)
获得sum:
return $query->selectRaw('DATE(start_time) AS date')
->selectRaw("(SELECT SUM(price) FROM `services_info` inner join `reservation_service_info` on `services_info`.`id` = `reservation_service_info`.`service_info_id` where `reservation_service_info`.`reservation_id` = reservations.id) as price")
->orderBy('date', 'ASC')
->groupBy('date')
->get();
我认为您的查询构建方式有点错误。我建议这样想:
return $query->select(\DB::raw('DATE(start_time) AS date'), \DB::raw('SUM(price) as price'))
->join('reservation_service_info', 'reservations.id', '=', 'reservation_service_info.reservation_id')
->join('services_info', 'services_info.id', '=', 'reservation_service_info.services_info_id')
->orderBy('date', 'ASC')
->groupBy('date')
->get();
如果$query
表是reservations
请尝试以下操作:
$users= DB::table('reservation_service_info')
->join('services_info', 'reservation_service_info.service_info_id', '=', 'services_info.id')
->join('reservations', 'reservation_service_info.reservation_id', '=', 'reservations.id')
->select('DATE(reservations.start_time) AS date','SUM(services_info.price) AS price')
->orderBy('reservations.start_time', 'ASC')
->groupBy('reservations.start_time')
->get();
是的,我试过了,但我得到了同样的效果,因为这个选择查询只是选择了一行…@user3806764你能编辑你的问题并显示想要的结果吗?
return $query->select(\DB::raw('DATE(start_time) AS date'), \DB::raw('SUM(price) as price'))
->join('reservation_service_info', 'reservations.id', '=', 'reservation_service_info.reservation_id')
->join('services_info', 'services_info.id', '=', 'reservation_service_info.services_info_id')
->orderBy('date', 'ASC')
->groupBy('date')
->get();
$users= DB::table('reservation_service_info')
->join('services_info', 'reservation_service_info.service_info_id', '=', 'services_info.id')
->join('reservations', 'reservation_service_info.reservation_id', '=', 'reservations.id')
->select('DATE(reservations.start_time) AS date','SUM(services_info.price) AS price')
->orderBy('reservations.start_time', 'ASC')
->groupBy('reservations.start_time')
->get();