Php 如何在新文件中插入mysql数据库？_Php_Mysql

Php 如何在新文件中插入mysql数据库？

php mysql

Php 如何在新文件中插入mysql数据库？,php,mysql,Php,Mysql,我想知道如何将mysql中的表放入一个新的file.php文件中我希望MySql表出现在页面上。这是我在MySql中插入数据的代码 <?php // Create connection $con = mysqli_connect("host", "id_", "password", "xxxxxx"); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: "

我想知道如何将mysql中的表放入一个新的file.php文件中

我希望MySql表出现在页面上。

这是我在MySql中插入数据的代码

<?php

// Create connection
$con = mysqli_connect("host", "id_", "password", "xxxxxx");

// Check connection
if (mysqli_connect_errno()) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$Task = $_POST['Task'];
$Date = $_POST['Date'];
$Desc = $_POST['Desc'];

$sql = "INSERT INTO tasklist (Task, Date, Description)
        VALUES ('$Task', '$Date', '$Desc')";

if (!mysqli_query($con, $sql)) {
    die('Error: ' . mysqli_error($con));
}
echo "1 record added";

mysqli_close($con);

?>

<html>
    <body>
        <form action="addtask.php" method="post">
            Task: <input type="text" name="Task">
            Date: <input type="text" id="datepicker" name="Date">
            Decrption:<textarea type="text" name="Desc"></textarea>
            <input type="submit" value="submit">
        </form>
    </body>
</html>

尝试以下代码：
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM Persons");

echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";

while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysqli_close($con);
?>



您还可以尝试以下示例代码：
在HTML表格中显示结果
以下示例选择与上述示例相同的数据，但将在HTML表中显示数据：
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM Persons");

echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";

while($row = mysqli_fetch_array($result)) {
  echo "<tr>";
  echo "<td>" . $row['FirstName'] . "</td>";
  echo "<td>" . $row['LastName'] . "</td>";
  echo "</tr>";
}

echo "</table>";

mysqli_close($con);
?>



上述代码的输出将为：

第一个代码来自此
中的“”，我希望MySQL表出现在页面上是什么意思？您的意思是要从表中检索行并用PHP在另一个页面上显示它们吗？请注意，您的代码容易受到SQL注入的攻击。现在是正确学习在MySQLi中使用的时候了。请仔细阅读并使用准备好的语句和绑定参数查看MySQLi示例。是的@MichaelBerkowski，关于注入，我知道，我不会接受它。我正在尝试先学习如何做。Ty