Php 如何显示包含次要成员详细信息的主要成员列表

Php 如何显示包含次要成员详细信息的主要成员列表,php,mysql,codeigniter,Php,Mysql,Codeigniter,我正在使用CodeIgniter,我的问题是关于MySQL查询。 我有两张表,分别是成员表和关系表 成员表 function format ( d ) { return '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'+ '<tr>'+ '<td>Full name:</td>'+

我正在使用CodeIgniter,我的问题是关于MySQL查询。 我有两张表,分别是成员表和关系表

成员表

     function format ( d ) {
    return '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'+
        '<tr>'+
            '<td>Full name:</td>'+
            '<td>'+d.name+'</td>'+
        '</tr>'+
        '<tr>'+
            '<td>Mobile number:</td>'+
            '<td>'+d.phone+'</td>'+
        '</tr>'+
        '<tr>'      
    '</table>';
}
$(document).ready(function() {
            var oTable =$('#all_list').DataTable( {
                "processing": true,
                // "serverSide": true,
                "pageLength": 10,
                "ajax": {
                    "url": baseUrl+ "/index.php/Search/Listdetails_ajax",
                    "type": "POST"
                },
                "columns": [
                   {
                "className":      'details-control',
                "orderable":      false,
                "data":           null,
                "defaultContent": ''
                    },
                { "data": "profile_pic","className":"img_list_pic",
                "render": function (data, type, full, meta) {
                return '<img src='+baseUrl+'/uploads/images/'+data+' class="search_pic">';
                }
                 },
                { "data": "name" },
                { "data": "phone" }
            ],
               "order": [[1, 'asc']],


            } );
    $('#all_list tbody').on('click', 'td.details-control', function () {
        var tr = $(this).closest('tr');
        var row = oTable.row( tr );

        if ( row.child.isShown() ) {
            // This row is already open - close it
            row.child.hide();
            tr.removeClass('shown');
        }
        else {
            // Open this row
            row.child( format(row.data()) ).show();
            tr.addClass('shown');
        }
    } );

} );
我要做的是,根据
member\u类型
将所有用户添加到member表中。如果成员类型为1,则该成员为主要成员;如果为2,则为次要成员

关系表

     function format ( d ) {
    return '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'+
        '<tr>'+
            '<td>Full name:</td>'+
            '<td>'+d.name+'</td>'+
        '</tr>'+
        '<tr>'+
            '<td>Mobile number:</td>'+
            '<td>'+d.phone+'</td>'+
        '</tr>'+
        '<tr>'      
    '</table>';
}
$(document).ready(function() {
            var oTable =$('#all_list').DataTable( {
                "processing": true,
                // "serverSide": true,
                "pageLength": 10,
                "ajax": {
                    "url": baseUrl+ "/index.php/Search/Listdetails_ajax",
                    "type": "POST"
                },
                "columns": [
                   {
                "className":      'details-control',
                "orderable":      false,
                "data":           null,
                "defaultContent": ''
                    },
                { "data": "profile_pic","className":"img_list_pic",
                "render": function (data, type, full, meta) {
                return '<img src='+baseUrl+'/uploads/images/'+data+' class="search_pic">';
                }
                 },
                { "data": "name" },
                { "data": "phone" }
            ],
               "order": [[1, 'asc']],


            } );
    $('#all_list tbody').on('click', 'td.details-control', function () {
        var tr = $(this).closest('tr');
        var row = oTable.row( tr );

        if ( row.child.isShown() ) {
            // This row is already open - close it
            row.child.hide();
            tr.removeClass('shown');
        }
        else {
            // Open this row
            row.child( format(row.data()) ).show();
            tr.addClass('shown');
        }
    } );

} );
在关系表中,我定义了用户的关系。例如,
primary_member_id
为1,然后次要成员为3和6,次要成员详细信息在成员表中可用

现在,我需要一个查询来显示列表中的所有主要成员,并与它们的次要成员名称和其他详细信息相关

我正在使用带有子行的数据表。这样我就可以在列表中显示主要成员的名称,并单击加号以显示次要成员

我尝试了下面的连接代码

SELECT * FROM `member` LEFT JOIN relation on member.id=relation.primary_member_id WHERE member.member_type=1
下面是上述查询的输出。在本例中,我将获得两次主要成员名称,以及如何显示次要成员名称

我需要一个输出

数据表

     function format ( d ) {
    return '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'+
        '<tr>'+
            '<td>Full name:</td>'+
            '<td>'+d.name+'</td>'+
        '</tr>'+
        '<tr>'+
            '<td>Mobile number:</td>'+
            '<td>'+d.phone+'</td>'+
        '</tr>'+
        '<tr>'      
    '</table>';
}
$(document).ready(function() {
            var oTable =$('#all_list').DataTable( {
                "processing": true,
                // "serverSide": true,
                "pageLength": 10,
                "ajax": {
                    "url": baseUrl+ "/index.php/Search/Listdetails_ajax",
                    "type": "POST"
                },
                "columns": [
                   {
                "className":      'details-control',
                "orderable":      false,
                "data":           null,
                "defaultContent": ''
                    },
                { "data": "profile_pic","className":"img_list_pic",
                "render": function (data, type, full, meta) {
                return '<img src='+baseUrl+'/uploads/images/'+data+' class="search_pic">';
                }
                 },
                { "data": "name" },
                { "data": "phone" }
            ],
               "order": [[1, 'asc']],


            } );
    $('#all_list tbody').on('click', 'td.details-control', function () {
        var tr = $(this).closest('tr');
        var row = oTable.row( tr );

        if ( row.child.isShown() ) {
            // This row is already open - close it
            row.child.hide();
            tr.removeClass('shown');
        }
        else {
            // Open this row
            row.child( format(row.data()) ).show();
            tr.addClass('shown');
        }
    } );

} );
/模型/


您可以使用两个查询来实现它

首先让所有主要成员显示主要成员列表

select * from Member m where m.member_type = 1;
其次,获取该主成员id的所有辅助成员

select * from Member m
join Relation r where m.member_id = r.secondary_member_id and 
r.primary_member_id = :primaryMemberId;

按照中所示的使用详细信息弹出窗口的想法,控制器将如下所示:

public function Listdetails_ajax(){  
   $draw = intval($this->input->get("draw"));
    $start = intval($this->input->get("start"));
    $length = intval($this->input->get("length"));
    $books = $this->Search_model->getTotalList_of_primary();

    $data['draw'] = 1;
    $data['recordsTotal'] = count($books);
    $data['recordsFiltered'] = count($books);
    foreach ($books as $key => $row) 
    {
        //print_r($row->customer_id);
        $arr_result = array(
                    "member_id" => base64_encode($this->encryption->encrypt($row->member_id)),
                    "profile_pic" => $row->profile_pic,
                    "name" => $row->first_name.' ' .$row->last_name,
                    "phone" => $row->phone,
                    "chss_no" => $row->chss_no,
                    "emp_id" => $row->emp_id,
                    "address" => $row->address
                    // "member_type" => $row->member_type
        );

         $array_secondary = array();
         $books_of_secondary = $this->Search_model->getTotalList_of_secondary($row->customer_id);
         foreach ($books_of_secondary as $key => $row) 
            {
                //print_r($row->customer_id);
                $arr_result2 = array(
                            "s_member_id" => base64_encode($this->encryption->encrypt($row->member_id)),
                            "s_profile_pic" => $row->profile_pic,
                            "s_name" => $row->first_name.' ' .$row->last_name,
                            "s_phone" => $row->phone,
                            "s_chss_no" => $row->chss_no,
                            "s_emp_id" => $row->emp_id,
                            "s_address" => $row->address
                );


                $array_secondary[] = $arr_result2;
            }
         $arr_result['secondary'] =  $array_secondary;  
         $data['data'][] = $arr_result;
      }
    echo json_encode($data);
    exit;
}
function format(d) {
    // d is the original data object for the row var val;
    if(d.secondary.length == 0) {
        return "There are no secondary members";
    }

    var display = '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'; 
    for (val of d.secondary) { 
        display += '<tr>' + '<td>Full name:</td>' + '<td>' + val.s_name + '</td>' + '</tr>' + '<tr>' + '<td>Mobile number:</td>' + '<td>' + val.s_phone + '</td>' + '</tr>';
    }
    display += '</table>';
    return display;
}
然后在format函数中,您将访问
secondary
字段以获取secondary数组。也许是这样:

public function Listdetails_ajax(){  
   $draw = intval($this->input->get("draw"));
    $start = intval($this->input->get("start"));
    $length = intval($this->input->get("length"));
    $books = $this->Search_model->getTotalList_of_primary();

    $data['draw'] = 1;
    $data['recordsTotal'] = count($books);
    $data['recordsFiltered'] = count($books);
    foreach ($books as $key => $row) 
    {
        //print_r($row->customer_id);
        $arr_result = array(
                    "member_id" => base64_encode($this->encryption->encrypt($row->member_id)),
                    "profile_pic" => $row->profile_pic,
                    "name" => $row->first_name.' ' .$row->last_name,
                    "phone" => $row->phone,
                    "chss_no" => $row->chss_no,
                    "emp_id" => $row->emp_id,
                    "address" => $row->address
                    // "member_type" => $row->member_type
        );

         $array_secondary = array();
         $books_of_secondary = $this->Search_model->getTotalList_of_secondary($row->customer_id);
         foreach ($books_of_secondary as $key => $row) 
            {
                //print_r($row->customer_id);
                $arr_result2 = array(
                            "s_member_id" => base64_encode($this->encryption->encrypt($row->member_id)),
                            "s_profile_pic" => $row->profile_pic,
                            "s_name" => $row->first_name.' ' .$row->last_name,
                            "s_phone" => $row->phone,
                            "s_chss_no" => $row->chss_no,
                            "s_emp_id" => $row->emp_id,
                            "s_address" => $row->address
                );


                $array_secondary[] = $arr_result2;
            }
         $arr_result['secondary'] =  $array_secondary;  
         $data['data'][] = $arr_result;
      }
    echo json_encode($data);
    exit;
}
function format(d) {
    // d is the original data object for the row var val;
    if(d.secondary.length == 0) {
        return "There are no secondary members";
    }

    var display = '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'; 
    for (val of d.secondary) { 
        display += '<tr>' + '<td>Full name:</td>' + '<td>' + val.s_name + '</td>' + '</tr>' + '<tr>' + '<td>Mobile number:</td>' + '<td>' + val.s_phone + '</td>' + '</tr>';
    }
    display += '</table>';
    return display;
}
函数格式(d){
//d是行var val的原始数据对象;
如果(d.secondary.length==0){
返回“没有辅助成员”;
}
变量显示=“”;
对于(d.secondary的val){
显示+='+'全名:'+'+val.s_姓名+'+'+'+'+'+'手机号码:'+'+'+val.s_电话+'+''+';
}
显示+='';
返回显示;
}

感谢您的回复,请给我一个时间来实现这一点。我对您的第二个查询感到困惑。你是说这个链接吗?从成员m连接关系r中选择*其中m.id=r.secondary\u member\u id和r.primary\u member\u id=m.id如何标识:primaryMemberId;?primaryMemberId是第二个查询的动态参数。它应该从您的第一个查询中获得。所以,基本上,一旦你有了一个主要成员列表,你点击一个主要成员来获得它的次要成员,然后你想在第二次查询中传递所选主要成员的id。但是我如何将该查询与CodeIgniter一起使用呢?添加了答案question@Adder,你能帮我解决下面的问题吗?并获取除
user…
以外的用户名,以便人们在您再次访问时能够认出您。