PHP数组-如何保存几行以匹配一长串字符

我在用PHP做数组时遇到了一个问题。 我不知道如何为以下情况编写代码：

$arrs = array("a@c", "cr", "exd", "hello", "gg%j", "hwa", "@", "8");

foreach ($arrs as $arr){
// if $arr does not belong to any characters from a to z, 
// then there must be some special character in it.
// Say for example, "a@c" will still be regarded as fine string, 
// since it contains normal characters a and c.
// another example, "gg%j" will also be fine, since it contains g and j.
}

---

您可以使用正则表达式和函数：

$arrs = array("abc", "cr", "exd", "hello", "gj", "hwa", "@", "8");
foreach ($arrs as $arr){
    // if $arr does not belong to any characters from a to z, 
    // then there must be some special character in it.
    if (!preg_match('/^[a-z]*$/', $arr)) {
        var_dump($arr);
    }
}

这将为您提供以下输出：

string '@' (length=1)
string '8' (length=1)

这里，正则表达式匹配：

• 字符串开头：

  ^

• a

  和

  z

  之间的任意字符数：

  [a-z]*

• 字符串结尾：

  $

---

因此，如果字符串包含不在

a

和

z

之间的任何内容，它将不匹配；和

var\u dump

字符串。

您可以使用正则表达式，函数：

$arrs = array("abc", "cr", "exd", "hello", "gj", "hwa", "@", "8");
foreach ($arrs as $arr){
    // if $arr does not belong to any characters from a to z, 
    // then there must be some special character in it.
    if (!preg_match('/^[a-z]*$/', $arr)) {
        var_dump($arr);
    }
}

$arrs = array("abc", "cr", "exd", "hello", "gj", "hwa", "@", "8");

foreach ($arrs as $arr){
// if $arr does not belong to any characters from a to z, 
// then there must be some special character in it.
   if(preg_match("/[a-zA-Z]+/",$arr)==0)
   {
       echo "There must be a special character in it.";
   }
}

这将为您提供以下输出：

string '@' (length=1)
string '8' (length=1)

这里，正则表达式匹配：

• 字符串开头：

  ^

• a

  和

  z

  之间的任意字符数：

  [a-z]*

• 字符串结尾：

  $

因此，如果字符串包含不在

a

和

z

之间的任何内容，它将不匹配；和

var\u dump

字符串

$arrs = array("abc", "cr", "exd", "hello", "gj", "hwa", "@", "8");

foreach ($arrs as $arr){
// if $arr does not belong to any characters from a to z, 
// then there must be some special character in it.
   if(preg_match("/[a-zA-Z]+/",$arr)==0)
   {
       echo "There must be a special character in it.";
   }
}

这听起来像是一个可疑的家庭作业问题

if(!preg_match("/^[a-z]*$/", $arr)) {
    // $arr has something other than just a to z in it
}

这听起来像是一个可疑的家庭作业问题

if(!preg_match("/^[a-z]*$/", $arr)) {
    // $arr has something other than just a to z in it
}