使用PHP邮件时不会发送变量

我将以下代码用作php文件，同时将我的信息表单发布为HTML文件，用户在填充数据后单击按钮。目前，在测试变量时，（$name、$email、$subject、$message）不会在电子邮件内容中发送，除了其余字符串

index.html

邮寄

sendmail.php

$name=@trim（带斜杠（$\u POST['name']）；
$email=@trim（斜杠（$_POST['email']）；
$subject=@trim（斜杠（$_POST['subject']）；
$message=@trim（带斜杠（$_POST['message']）；
$email_from=$email；
$email\u发送至dhananjayan322@gmail.com';//替换为您的电子邮件
$body='Name:'$名称“\n\n”。”电邮：‘$电子邮件“\n\n”。“主题：”$主题“\n\n”。”消息：'$消息
$success=@mail（$email_to，$subject，$body，'From:'）；

输出

---

您必须在主题之前添加一个单引号：

$name = @trim(stripslashes($_POST['name'])); 
$email = @trim(stripslashes($_POST['email'])); 
$subject = @trim(stripslashes($_POST['subject'])); 
$message = @trim(stripslashes($_POST['message'])); 

$email_from = $email;
$email_to = 'dhananjayan322@gmail.com'; // replace with your email

$body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" . 'Subject: ' . $subject . "\n\n" . 'Message: ' . $message;

$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');

echo json_encode($status);
die; 

$name=@trim（带斜杠（$\u POST['name']）；
$email=@trim（斜杠（$_POST['email']）；
$subject=@trim（斜杠（$_POST['subject']）；
$message=@trim（带斜杠（$_POST['message']）；
$email_from=$email；
$email\u发送至dhananjayan322@gmail.com'; // 替换为您的电子邮件
$body='Name:'$名称“\n\n”。”电邮：‘$电子邮件“\n\n”。”主题：‘$主题“\n\n”。”消息：'$消息
$success=@mail（$email_to，$subject，$body，'From:'）；
echo json_编码（$status）；
死亡

它不工作了。。。我在subject前面加了一个引号，也许在所有被抑制的函数调用中隐藏了一个错误。。尝试删除它们&正面面对错误。。！

$name = @trim(stripslashes($_POST['name'])); 
$email = @trim(stripslashes($_POST['email'])); 
$subject = @trim(stripslashes($_POST['subject'])); 
$message = @trim(stripslashes($_POST['message'])); 

$email_from = $email;
$email_to = 'dhananjayan322@gmail.com';//replace with your email

$body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" .' Subject: ' . $subject . "\n\n" . 'Message: ' . $message;

$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');

$name = @trim(stripslashes($_POST['name'])); 
$email = @trim(stripslashes($_POST['email'])); 
$subject = @trim(stripslashes($_POST['subject'])); 
$message = @trim(stripslashes($_POST['message'])); 

$email_from = $email;
$email_to = 'dhananjayan322@gmail.com'; // replace with your email

$body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" . 'Subject: ' . $subject . "\n\n" . 'Message: ' . $message;

$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');

echo json_encode($status);
die;