Php 用条件计算行数？

在你说之前，我已经试过了所有的方法

我试图用两个WHERE子句计算mysqli查询中的行数

if (isset($_POST['member_name']) and isset($_POST['memeber_password'])) {
    $member_name_input = mysqli_real_escape_string($query, $_POST['member_name']);
    $member_password_input = mysqli_real_escape_string($query, $_POST['member_password']);

    $result = mysqli_query($query, "SELECT count(*) AS member_count FROM `members` WHERE `member_name` = '$member_name_input' AND `member_password` = '$member_password_input'") or die(mysqli_error($query));
    $counter = $row['member_count'];

    if ($counter = 1) {
        $result = mysqli_query($query, "SELECT * FROM `members` WHERE `member_name`='$member_name_input' AND `member_password`='$member_password_input'") or die(mysqli_error($query));
        $row = mysqli_fetch_array($result);
        $member_suspended = $row['member_suspended'];
        $member_validation = $row['member_validation'];
    }

    if ($member_suspended < time() and $member_validation = 2) {
        $_SESSION['member_id'] = $row['member_id'];
        echo $counter;
    } elseif ($member_suspended >= time()) {
        $suspension_date = date('d. m. y.', $member_suspended);
        echo '<div class="left_container"><h3>You are suspended until '.$suspension_date.'.</h3></div>';
    } elseif ($member_validation = 1) {
        echo '<div class="left_container"><h3>Your account has not been confirmed, yet.</h3></div>';
    } else {
        echo '<div class="left_container"><h3>Login unsuccessful.</h3></div>';
    }
} 

及

我只是想找到一种方法，让我的用户成功登录，并向无效的登录尝试显示错误消息

感谢您花时间通读本文并尽力提供帮助。：）

这将始终=1，假设你的意思是

if ($counter == 1) {

---

您需要先从结果中提取行，然后才能设置计数器

改变

$result = mysqli_query($query, "SELECT count(*) AS member_count FROM `members` WHERE `member_name` = '$member_name_input' AND `member_password` = '$member_password_input'") or die(mysqli_error($query));
$counter = $row['member_count'];

到

---

以下查询非常适合我：从

members

中选择count（*）作为member\u count，其中

member\u name

='$member\u name\u input'和

member\u password

='$member\u password\u input'

---

如果没有找到匹配的记录，则重新返回0，否则将返回匹配的记录数。

非常感谢，我不敢相信我犯了这么愚蠢的错误。工作起来很有魅力。：）这种情况时有发生：）-请记住在排除故障时回显VAR$计数器会回显“1”，然后您可以更改查询或其他变量，它仍然是1，并且您知道它不是查询。它并不总是透露，但往往有帮助

if ($counter = 1) {

if ($counter == 1) {

$result = mysqli_query($query, "SELECT count(*) AS member_count FROM `members` WHERE `member_name` = '$member_name_input' AND `member_password` = '$member_password_input'") or die(mysqli_error($query));
$counter = $row['member_count'];

$result = mysqli_query($query, "SELECT count(*) AS member_count FROM `members` WHERE `member_name` = '$member_name_input' AND `member_password` = '$member_password_input'") or die(mysqli_error($query));
$row = mysqli_fetch_assoc($result);
$counter = $row['member_count'];