Php 使用Haversine进行SQL搜索

Php 使用Haversine进行SQL搜索,php,doctrine,coordinates,Php,Doctrine,Coordinates,我想通过坐标进行搜索,也就是说,我想有一个这样的函数: function getLocationsInCircle($lat, $long, $minDist, $maxDist){ //return all the places that are at least $minDist //kilometers away and no more than $maxDist kilometers away } 我有一个“位置”表,它存储所有位置ID及其纬度和经度 哈弗森公式对我想

我想通过坐标进行搜索,也就是说,我想有一个这样的函数:

function getLocationsInCircle($lat, $long, $minDist, $maxDist){
    //return all the places that are at least $minDist 
    //kilometers away and no more than $maxDist kilometers away
}
我有一个“位置”表,它存储所有位置ID及其纬度和经度

哈弗森公式对我想做的足够好了

6371 * ACOS(SIN(RADIANS( $lat )) * SIN(RADIANS( latitude )) + COS(RADIANS( $lat )) * COS(RADIANS( latitude )) * COS(RADIANS( longitude ) - RADIANS( $long )))
我只是不知道如何在条令中运行该查询。

试试这个:

Doctrine_query::create()->select('id')
    ->addSelect("(6371 * ACOS(SIN(RADIANS($latitude)) * SIN(RADIANS(l.latitude)) + COS(RADIANS($latitude)) * COS(RADIANS(l.latitude)) * COS(RADIANS(l.longitude) - RADIANS($longitude)))) as Distance")
    ->from('Location l')
    ->having("Distance > $minDist AND Distance < $maxDist");
Doctrine\u query::create()->select('id')
->addSelect(((6371*ACOS(SIN(弧度($纬度))*SIN(弧度(l纬度))+COS(弧度($纬度))*COS(弧度(l纬度))*COS(弧度(l经度)-弧度($经度))作为距离)
->从('位置l')
->有(“距离>$Minist,距离<$maxDist”);