Php 计算数组中的和
我有以下数组Php 计算数组中的和,php,arrays,sum,Php,Arrays,Sum,我有以下数组 foreach ($reviews as $review){ $sqlreviews[] = array ( 'score' => $review['value'] + $review['location'] + $review['service'] + $review['rooms'] + $review['cleanliness'], ); 以下回波输出11 25 foreach ($sqlreviews as $review1) { echo" ".$
foreach ($reviews as $review){
$sqlreviews[] = array (
'score' => $review['value'] + $review['location'] + $review['service'] + $review['rooms'] + $review['cleanliness'],
);
以下回波输出11 25
foreach ($sqlreviews as $review1) {
echo"
".$review1['score']."
";
}
如何对上述输出求和,并将总计86传递给变量?我不知道数组是如何设置的,但您可以使用以下函数输出数组和:
$a = array_sum($array);
echo $a;
我假设您有这样一个数组=>['reviews']=>('value'=>0,'location'=>1,'service'=>1,'rooms'=>2,'cleanlines'=>2) 如果只有一组数据不需要使用PHP 5.5的函数进行迭代,则可以执行以下操作:
$sum = 0;
foreach ($sqlreviews as $review1) {
$sum += $review1['score'];
}
echo $sum;
$total = array_sum(
array_column(
$reviews,
'score'
)
);
$total = array_sum(
array_map(
function($value) {
return $value['score'];
},
$reviews
)
);
对于早期版本的PHP,您可以执行以下操作:
$total = array_sum(
array_column(
$reviews,
'score'
)
);
$total = array_sum(
array_map(
function($value) {
return $value['score'];
},
$reviews
)
);
或