Php MySQL查询中的多维数组

我正在尝试使用

start\u date

和

end\u date

值创建多维数组

$array = [];
$i = 0;

while ($row = mysqli_fetch_assoc($result)) {
    $array[$i]['start_date'] = $row['current_status_start_time'];
    $array[$i]['end_date'] = '';
    $i++;
}
print_r($array);

返回的数组如下所示：

  Array ( 
    [0] => Array (
         [start_date] => 2013-07-25 11:18:42
         [end_date] => )
    [1] => Array (
         [start_date] => 2013-07-26 05:24:08
         [end_date] => )
    [2] => Array ( 
         [start_date] => 2013-07-31 17:25:05
         [end_date] => )
 ) 

foreach($mainArray as $key => $value)
{
    $next = $key + 1;

    if(!is_null($mainArray[$next]['start_date']))
    {
        $mainArray[$key]['end_date'] = $mainArray[$next]['start_date'];
    }
    else
    {
        $mainArray[$key]['end_date'] = current_date;
    }
}

print_r($main_array);

结束日期

应获取下一个数组

[开始日期]

节点值：

        Array ( 
    [0] => Array (
         [start_date] => 2013-07-25 11:18:42
         [end_date] =>   **2013-07-26 05:24:08**)
    [1] => Array (
         [start_date] => **2013-07-26 05:24:08**
         [end_date] =>   2013-07-31 17:25:05)
    [2] => Array ( 
         [start_date] => 2013-07-31 17:25:05
         [end_date] => current_date)
 ) 

正如您在上一个代码示例中所看到的，

array[0][end\u date]

应该获取

array[1][start\u date]

值，依此类推，最后一个数组

end\u date

应该获取当前时间值，因为存在数组的末尾

---

我应该使用第二个循环来实现这一点吗？或者有其他更简单的方法吗？

这应该可以满足您的需求：

$array = [];
$i = 0;

while ($row = mysqli_fetch_assoc($result)) {
    $array[$i]['start_date'] = $row['current_status_start_time'];
    $array[$i]['end_date'] = '';
    if ($i > 0){
        // if we are pass the first item set the previous item to the current start date
        $array[$i-1]["end_date"] = $array[$i]['start_date'];
    }
    $i++;
}
// fill in the last end_date with the current_date
$array[$i]["end_date"] = date("Y-m-d H:i:s");
print_r($array);

---

这会让你得到你想要的：

$array = [];
$i = 0;

while ($row = mysqli_fetch_assoc($result)) {
    $array[$i]['start_date'] = $row['current_status_start_time'];
    $array[$i]['end_date'] = '';
    if ($i > 0){
        // if we are pass the first item set the previous item to the current start date
        $array[$i-1]["end_date"] = $array[$i]['start_date'];
    }
    $i++;
}
// fill in the last end_date with the current_date
$array[$i]["end_date"] = date("Y-m-d H:i:s");
print_r($array);

---

我会打个圈。大概是这样的：

  Array ( 
    [0] => Array (
         [start_date] => 2013-07-25 11:18:42
         [end_date] => )
    [1] => Array (
         [start_date] => 2013-07-26 05:24:08
         [end_date] => )
    [2] => Array ( 
         [start_date] => 2013-07-31 17:25:05
         [end_date] => )
 ) 

foreach($mainArray as $key => $value)
{
    $next = $key + 1;

    if(!is_null($mainArray[$next]['start_date']))
    {
        $mainArray[$key]['end_date'] = $mainArray[$next]['start_date'];
    }
    else
    {
        $mainArray[$key]['end_date'] = current_date;
    }
}

print_r($main_array);

---

我会打个圈。大概是这样的：

  Array ( 
    [0] => Array (
         [start_date] => 2013-07-25 11:18:42
         [end_date] => )
    [1] => Array (
         [start_date] => 2013-07-26 05:24:08
         [end_date] => )
    [2] => Array ( 
         [start_date] => 2013-07-31 17:25:05
         [end_date] => )
 ) 

foreach($mainArray as $key => $value)
{
    $next = $key + 1;

    if(!is_null($mainArray[$next]['start_date']))
    {
        $mainArray[$key]['end_date'] = $mainArray[$next]['start_date'];
    }
    else
    {
        $mainArray[$key]['end_date'] = current_date;
    }
}

print_r($main_array);