Plsql 拆分正则表达式并循环

我需要在一个连接中循环，我想我已经写过了。 我正在发布代码

    select listagg(request_num,',') within group (order by request_num) as request_num,segmentation_name from (
select MST.REQUEST_NUM,seg_dtls.SEGMENT_NAME,LAST_UPDATED_date,seg_dtls.segmentation_name from 
(select  * from rp_sr_master ) Mst,
(select  SUBSTR(ANSWER,1,INSTR (ANSWER, '~', 1)-1) AS SM_ID,sr_id from rp_sR_details 
WHERE Q_ID in (SELECT Q_ID FROM RP_QUESTIONS WHERE field_id='LM_LRE_Q6')
    ) Dtls, (select SM_ID, SQL_STATEMENT, CREATION_DATE, UPDATED_DATE, SEGMENT_NAME,segmentation_name ,TOTAL_COUNT
from rp_sEGMENT_master ) seg_dtls
where Dtls.SM_ID=seg_dtls.SM_ID
and Dtls.sr_id=Mst.sr_id)
group by segmentation_name;

我在这里面临的问题是：

(select  SUBSTR(ANSWER,1,INSTR (ANSWER, '~', 1)-1) AS SM_ID,sr_id from rp_sR_details 
    WHERE Q_ID in (SELECT Q_ID FROM RP_QUESTIONS WHERE field_id='LM_LRE_Q6')
        )

在上面的代码中，答案如下：

2603~NG非IaaS IT专业人士^2600~NG非IaaS高级IT ^2598~NG数据分析高级IT专业人士^2595~尼日利亚数据分析IT专业人士
它只选择第一个数字2603，其他数字将被忽略

有没有办法让我把“答案”中的所有数字循环一遍。
我在寻找创意

谢谢。
一个想法是使用一种方法将逗号分隔的字符串拆分为行，
您可以在以下答案中找到此方法的示例：



上述解决方案使用
regexp\u substr
函数。

如果深入了解Oracle的详细信息，您会发现其中有可选的
position
参数


此参数可与此答案中所示的解决方案组合：


（即
从DUAL CONNECT逐层选择n层谢谢，我正在努力学习。下面是我的更多疑问。“\d+”在表达式中查找数字。我遇到的情况是，答案类似于345~nas 2016^234~ras2034^ 34_234^帮助3。在这里，我尝试了一个regsub来查找^and~之间的数字，但第一个数字没有^这个[0-9]*（？=~）。
with xx as (
select '2603~NG non IaaS  IT Professional^2600~NG non IaaS Senior '
       || 'IT^2598~NG data profiling SENIOR IT professional^2595~Nigeria '
       || 'data profiling IT professiona' as answer
from dual
)
select LEVEL AS n, regexp_substr( answer, '\d+',  1, level) as nbr
from xx
connect by level <= 6
;

N |NBR  |
--|-----|
1 |2603 |
2 |2600 |
3 |2598 |
4 |2595 |
5 |     |
6 |     |

with xx as (
select '2603~NG non IaaS  IT Professional^2600~NG non IaaS Senior '
       || 'IT^2598~NG data profiling SENIOR IT professional^2595~Nigeria '
       || 'data profiling IT professiona' as answer
from dual
)
select LEVEL AS n, regexp_substr( answer, '\d+',  1, level) as nbr
from xx
connect by regexp_substr( answer, '\d+',  1, level) IS NOT NULL
;

N |NBR  |
--|-----|
1 |2603 |
2 |2600 |
3 |2598 |
4 |2595 |

--  source data
WITH xx as (
select 1 AS id,
       '2603~NG non IaaS  IT Professional^2600~NG non IaaS Senior '
       || 'IT^2598~NG data profiling SENIOR IT professional^2595~Nigeria '
       || 'data profiling IT professiona' as answer
from dual
UNION ALL
select 2 AS id,
       '11111~NG non IaaS  IT Professional^22222~NG non IaaS Senior '
       || 'IT^2598~NG data 33333 profiling SENIOR IT professional^44~Nigeria '
       || 'data profiling 5 IT professiona 66' as answer
from dual
)
-- end of source data


SELECT t.ID, t1.n, t1.nbr
FROM xx t
CROSS JOIN LATERAL (
        select LEVEL AS n, regexp_substr( t.answer, '\d+',  1, level) as nbr
        from dual
        connect by regexp_substr( t.answer, '\d+',  1, level) IS NOT NULL
) t1;

ID |N |NBR   |
---|--|------|
1  |1 |2603  |
1  |2 |2600  |
1  |3 |2598  |
1  |4 |2595  |
2  |1 |11111 |
2  |2 |22222 |
2  |3 |2598  |
2  |4 |33333 |
2  |5 |44    |
2  |6 |5     |
2  |7 |66    |