Postgresql 类型numeric的输入语法无效："&引用；

我正在从数据库中选择数据，如果列不包含任何值，它将输出“blank”，尽管当我执行我尝试搜索的查询时遇到以下错误，但我得到的答案不起作用。 这似乎是数字的错误

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我假设您尝试获取文本，而不是整数，因此您将看到euther一些数字，如

1234

或空字符串```，而不是零，以便将

数值

转换为文本，例如：

ELSE npi.temp\u成员号：：text

然后你会得到更糟糕的结果

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（适用于所有非文本字段，如果

NULL

，则预期为空字符串）

错误消息为退出清除：您试图使用空字符串作为数字。那不行。案例中的所有值必须是相同的类型。

SELECT Concat(npi.first_name, ' ', npi.middle_name, ' ', npi.last_name) AS othername, npi.nhif_persons_identity_serial,
  CASE WHEN npi.person_identity_number IS NULL THEN '' WHEN Trim(npi.person_identity_number) = '' THEN ''
    ELSE npi.contact_email END, npi.biometric_member_number, npi.birth_certificate_number, npi.national_id_number, CASE
    WHEN npi.national_passport_number IS NULL THEN '' WHEN Trim(npi.national_passport_number) = '' THEN ''
    ELSE npi.national_passport_number END, CASE WHEN npi.national_pin_number IS NULL THEN ''
    WHEN Trim(npi.national_pin_number) = '' THEN '' ELSE npi.national_pin_number END, CASE
    WHEN npi.contact_email IS NULL THEN '' WHEN Trim(npi.contact_email) = '' THEN '' ELSE npi.contact_email END, CASE
    WHEN npi.address_district IS NULL THEN '' WHEN Trim(npi.address_district) = '' THEN '' ELSE npi.address_district
  END, CASE WHEN npi.address_location IS NULL THEN '' WHEN Trim(npi.address_location) = '' THEN ''
    ELSE npi.address_location END, CASE WHEN npi.address_county IS NULL THEN ''
    WHEN Trim(npi.address_county) = '' THEN '' ELSE npi.address_county END, CASE WHEN npi.work_code IS NULL THEN ''
    WHEN Trim(npi.work_code) = '' THEN '' ELSE npi.work_code END, CASE WHEN npi.address_physical IS NULL THEN ''
    WHEN Trim(npi.address_physical) = '' THEN '' ELSE npi.address_physical
  END
  , npi.date_of_birth  , npi.date_registered, npi.date_added,CASE WHEN npi.gender IS NULL THEN ''
    WHEN Trim(npi.gender) = '' THEN '' ELSE npi.gender
  END
  , npi.first_name, npi.middle_name, npi.last_name,

   CASE WHEN npi.marital_status IS NULL THEN ''
    WHEN Trim(npi.marital_status) = '' THEN '' ELSE npi.marital_status
  END
  ,CASE WHEN npi.contact_address IS NULL THEN ''
    WHEN Trim(npi.contact_address) = '' THEN '' ELSE npi.contact_address
  END
  ,CASE WHEN npi.contact_telephone IS NULL THEN ''
    WHEN Trim(npi.contact_telephone) = '' THEN '' ELSE npi.contact_telephone
  END
  ,CASE WHEN npi.contact_mobile IS NULL THEN ''
    WHEN Trim(npi.contact_mobile) = '' THEN '' ELSE npi.contact_mobile
  END
  ,CASE WHEN npi.mobile_contact_detail IS NULL THEN ''
    WHEN Trim(npi.mobile_contact_detail) = '' THEN '' ELSE npi.mobile_contact_detail
  END
  ,CASE WHEN npi.temp_member_number IS NULL THEN ''
     ELSE npi.temp_member_number
  END
  ,CASE WHEN npi.national_nhif_number IS NULL THEN ''
    WHEN Trim(npi.national_nhif_number) = '' THEN '' ELSE npi.national_nhif_number
  END
  ,CASE WHEN nbci.facial_full_image IS NULL THEN ''
    WHEN Trim(nbci.facial_full_image) = '' THEN '' ELSE nbci.facial_full_image
  END
  ,CASE WHEN nbci.facial_scaled_image IS NULL THEN ''
    WHEN Trim(nbci.facial_scaled_image) = '' THEN '' ELSE nbci.facial_scaled_image
  END

FROM nhif_persons_identities npi
  INNER JOIN nhif_biometric_cards nbc ON npi.nhif_persons_identity_serial = nbc.nhif_persons_identity_serial
  INNER JOIN nhif_biometric_card_images nbci ON nbci.nhif_biometric_card_serial = nbc.nhif_biometric_card_serial
WHERE npi.nhif_persons_identity_serial = 293182

ERROR:  invalid input syntax for type numeric: ""
LINE 35:   ,CASE WHEN npi.temp_member_number IS NULL THEN ''
                                                          ^

********** Error **********

ERROR: invalid input syntax for type numeric: ""
SQL state: 22P02
Character: 2318