Postgresql PL/PgSQL混淆错误

我已经为Postgres编写了以下函数，当通过pgAdmin安装时，它在我的本地windows计算机上运行良好。当我尝试将其添加到基于linux的服务器安装时，会抛出编译错误：

查询：选择$1拆分\u部分$2'，，$3 上下文：PL/PgSQL函数中的SQL语句在第34行附近拆分字

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我浏览了谷歌和文档，但找不到任何相关的东西。我很困惑！非常感谢您提供的任何帮助

尚未读取函数，但错误消息通常表示变量与列具有相同的名称。用u作为变量名的前缀通常是避免该消息的一种好方法，它使plpgsql函数更具可读性

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此外，代码中至少出现了一个=，看起来应该是a:=。plpgsql原谅了这一点，但你不应该指望它。

第34行有保留字计数。这是我的第一个猜测。

CREATE OR REPLACE FUNCTION splitwords(text, int)
  RETURNS text AS
$BODY$
DECLARE
inwords ALIAS FOR $1;
posn INTEGER;
existcount INTEGER;
incurrdataid ALIAS FOR $2;
currdataid INTEGER;
currwordid INTEGER;
length INTEGER;
wordpos INTEGER;
newword TEXT;
BEGIN
currdataid:=incurrdataid;
currdataid:=currdataid-1; --corrects for auto-increment error
posn:=1;
WHILE posn<11 LOOP
IF split_part(inwords,' ',posn)='' THEN
-- If no more words are available
    EXIT;
ELSE
--If not at the end of the words
    IF (SELECT wordID FROM words WHERE word=split_part(inwords,' ',posn))>0 THEN
    --If word is already in lexicon
        currwordid:=(SELECT wordID FROM words WHERE word=split_part(inwords,' ',posn))::INTEGER;
        existcount:= (SELECT count FROM words WHERE word=split_part(inwords,' ',posn))::INTEGER;
        UPDATE words SET count=existcount+1 WHERE word=split_part(inwords,' ',posn);
        INSERT INTO wordsdata(wordid,dataid) VALUES (currwordid,currdataid);
        posn:=posn+1;
    ELSE
    --If word is new
        newword=split_part(inwords,' ',posn);
        INSERT INTO words(word,count) VALUES (newword,1);
        currwordid:=(SELECT wordID FROM words WHERE word=split_part(inwords,' ',posn))::INTEGER;
        INSERT INTO wordsdata(wordid,dataid) VALUES (currwordid,currdataid);
        length:=length(split_part(inwords,' ',posn));
        wordpos:=1;
        WHILE wordpos<(length+1) LOOP
            INSERT INTO searchchar(searchstr,wordid) VALUES (substring(split_part(inwords,' ',posn),1,wordpos),currwordid);
            wordpos=wordpos+1;
        END LOOP;
        posn:=posn+1;
    END IF;
END IF;
END LOOP;

RETURN 'rows added';
END
$BODY$
  LANGUAGE plpgsql VOLATILE
  COST 100;