具有多列和星期日的PostgreSQL交叉表查询

我试图通过将几个列分组来创建一个透视：用户id、名称、周数和当天的名称。 当前请求未给出所需的结果。 我需要帮助

这是我的桌子：

这是我当前的请求：

以下是我想要得到的结果。

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您可以只使用条件聚合：

SELECT user_id, name, week_number
       MAX(price) FILTER (WHERE day_name = 'Sunday') as Sunday,
       MAX(price) FILTER (WHERE day_name = 'Monday') as Monday,
       MAX(price) FILTER (WHERE day_name = 'Tuesday') as Tuesday,
       MAX(price) FILTER (WHERE day_name = 'Wednesday') as Wednesday,
       MAX(price) FILTER (WHERE day_name = 'Thursday') as Thursday,
       MAX(price) FILTER (WHERE day_name = 'Friday') as Friday,
       MAX(price) FILTER (WHERE day_name = 'Saturday') as Saturday
FROM table_1
GROUP BY user_id, name, week_number
ORDER BY user_id, name, week_number;

编辑：

您可以编写相同的逻辑而不使用

过滤器

：

       MAX(CASE WHEN day_name = 'Sunday' THEN price END) as Sunday,

---

您可以只使用条件聚合：

SELECT user_id, name, week_number
       MAX(price) FILTER (WHERE day_name = 'Sunday') as Sunday,
       MAX(price) FILTER (WHERE day_name = 'Monday') as Monday,
       MAX(price) FILTER (WHERE day_name = 'Tuesday') as Tuesday,
       MAX(price) FILTER (WHERE day_name = 'Wednesday') as Wednesday,
       MAX(price) FILTER (WHERE day_name = 'Thursday') as Thursday,
       MAX(price) FILTER (WHERE day_name = 'Friday') as Friday,
       MAX(price) FILTER (WHERE day_name = 'Saturday') as Saturday
FROM table_1
GROUP BY user_id, name, week_number
ORDER BY user_id, name, week_number;

编辑：

您可以编写相同的逻辑而不使用

过滤器

：

       MAX(CASE WHEN day_name = 'Sunday' THEN price END) as Sunday,

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谢谢，它适用于PostgreSQL 9.4.4版本。PostgreSQL 9.3.22版本是否有等效的过滤器？第二种解决方案也适用。感谢您的支持。感谢它与PostgreSQL 9.4.4版本配合使用。PostgreSQL 9.3.22版本是否有等效的过滤器？第二种解决方案也适用。谢谢你的支持。