Postgresql 如何将复杂的组转换为续集?
我的SQL查询是Postgresql 如何将复杂的组转换为续集?,postgresql,sequelize.js,Postgresql,Sequelize.js,我的SQL查询是 SELECT t."id", t."topicText", COUNT(t."id") AS topicCount FROM "WorkbookQuestions" wq, "Workbooks" w, "Questions" q, "Topics" t WHERE w."StudentId" = 3 AND wq."QuestionId" = q."id" AND wq."WorkbookId" = w."id" AND q."TopicId" = t
SELECT t."id", t."topicText", COUNT(t."id") AS topicCount
FROM "WorkbookQuestions" wq, "Workbooks" w, "Questions" q, "Topics" t
WHERE w."StudentId" = 3
AND wq."QuestionId" = q."id"
AND wq."WorkbookId" = w."id"
AND q."TopicId" = t."id"
GROUP BY "t"."id"
ORDER BY "topiccount" DESC
如何在Sequelize
代码中编写此代码,以避免直接编写SQL?还是不可能
这是我迄今为止尝试过的(未成功的):
只要看一下,我就会这样写代码
db.Workbook.findAll({
attributes: ['wbquestion.question.topic.id', [db.sequelize.fn('COUNT', db.sequelize.col('wbquestion.question.topic.id'))], 'topiccount'],
include: [
{
model: db.WorkbookQuestion,
as: wbquestion,
where: {
id: wbquestion.workbookId
},
include: [
model: db.Question,
as: question,
where: {
id: wbquestion.questionId
},
include: [
model: db.Topic,
as: topic,
where: {
id: question.topicId
}
]
]
}
],
where: {
studentId : 3
}
group: ['topic.id']
});
通过分别定义模型和关系并在之后使用即时加载,您可能可以获得更可读的代码
编辑:
生成迁移和模型
node_modules/.bin/sequelize model:create --name Student --attributes firstName:string,lastName:string
node_modules/.bin/sequelize model:create --name Topic --attributes topicText:string
node_modules/.bin/sequelize model:create --name Question --attributes TopicId:integer
node_modules/.bin/sequelize model:create --name Workbook --attributes studentId:integer
node_modules/.bin/sequelize model:create --name WorkbookQuestion --attributes QuestionId:integer,WorkbookId:integer
一个简单的程序,用于测试控制台日志中的查询
var Sequelize = require("sequelize");
var models = require('./models/index');
models.WorkbookQuestion.belongsTo(models.Question, {foreignKey: 'QuestionId'});
models.WorkbookQuestion.belongsTo(models.Workbook, {foreignKey: 'WorkbookId'});
models.Question.hasOne(models.WorkbookQuestion);
models.Workbook.hasOne(models.WorkbookQuestion);
models.Workbook.belongsToMany(models.Question, {through: models.WorkbookQuestion});
models.Workbook.belongsToMany(models.Topic, {through: models.Question});
var res = models.Workbook.findAll({
attributes: ['topicId', Sequelize.fn('count', Sequelize.col('topiccount'))],
include: [models.WorkbookQuestion, models.Question, models.Topic],
where: {
studentId: 3
},
group: ['topic.id']
}).then(function(data) {
console.log(data);
}).catch(function(err) {
console.trace(err);
});
结果是:
SequelizeDatabaseError:列Topics.Question.WorkbookId不存在
也许您可以修复模型之间的关系,或者您应该不使用findAll功能创建查询。有错误吗?Sequelize为您的示例生成的查询是什么样子的?
var Sequelize = require("sequelize");
var models = require('./models/index');
models.WorkbookQuestion.belongsTo(models.Question, {foreignKey: 'QuestionId'});
models.WorkbookQuestion.belongsTo(models.Workbook, {foreignKey: 'WorkbookId'});
models.Question.hasOne(models.WorkbookQuestion);
models.Workbook.hasOne(models.WorkbookQuestion);
models.Workbook.belongsToMany(models.Question, {through: models.WorkbookQuestion});
models.Workbook.belongsToMany(models.Topic, {through: models.Question});
var res = models.Workbook.findAll({
attributes: ['topicId', Sequelize.fn('count', Sequelize.col('topiccount'))],
include: [models.WorkbookQuestion, models.Question, models.Topic],
where: {
studentId: 3
},
group: ['topic.id']
}).then(function(data) {
console.log(data);
}).catch(function(err) {
console.trace(err);
});