Python 2.7 python根据用户输入打印输出

这是一个简单的代码，脚本将询问用户的姓名、年龄、性别和身高，并基于此给出输出。我目前的代码如下：

print "What is your name?"
name = raw_input()
print "How old are you?"
age = raw_input()
print "Are you male? Please answer Y or N"
sex = raw_input()
if sex == "Y" or sex == "y":
    sex = "Male"
else:
    sex = "Female"
print "How tall are you? Please enter in feet such as 5.5"
height = raw_input()

if sex == "Male" and height >= 6.0:
    t = "You are tall for a male"
elif sex == "Male" and height < 6.0:
    t = "You are below average for a male"

elif sex == "Female" and height >= 5.5:
    t = "You are tall for a female"
else:
    t = "You are below average for a female"


print "Hello %s. You are %s years old and %s feet tall. %s." % (name, age, height, t)

我挂断了if，elif，else的声明：

if sex == "Male" and height >= 6.0:
    t = "You are tall for a male"
elif sex == "Male" and height < 6.0:
    t = "You are below average for a male"

elif sex == "Female" and height >= 5.5:
    t = "You are tall for a female"
else:
    t = "You are below average for a female"

代码将区分性别是男性还是女性，但始终会返回xxx的身高。我不知道如何获得You is below average返回值。

这是因为原始输入返回的是字符串，而不是浮点，在Python 2中，字符串和浮点之间的比较方式总是相同的

>>> "1.0" > 6.0
True

这样做：

height = float(raw_input())

高度=输入也会起作用，但由于评估的原因，不鼓励使用安全问题

注意：这在Python3中得到了修复，可能是因为它不是很有用，而且容易出错：尝试这样做会导致

TypeError: unorderable types: str() > float()

这是明确的，会让你意识到你的错误

注意：如果您试图比较年龄=原始输入，则同样的问题应该是年龄=内部输入