Python 2.7 名称'；自我'；未在Python中定义

有人能告诉我需要做什么来解决我在下面识别的线路上遇到的“名称‘自我’未定义”错误吗

class FulfillWhseOrderAction(object):

    def __init__(self, name):
        self._action_name = name
        self._as = actionlib.SimpleActionServer(self._action_name, pkg_commands.msg.FulfillWhseOrderAction, execute_cb=self.execute_cb)
        self._as.start()

    # *** ERROR HAPPENING HERE: ***
    rospy.loginfo('%s: Executing warehouse order' % self._action_name)

if __name__ == '__main__':
    rospy.init_node('node_ReceiveWhseOrder')
    FulfillWhseOrderAction(rospy.get_name())
    rospy.spin()

---

self

是发送到

\uuuu init\uuu

函数的变量（称之为对象）。因此，您无法从函数外部访问它。将发生错误的行缩进函数内部

class FulfillWhseOrderAction(object):

    def __init__(self, name):
        self._action_name = name
        self._as = actionlib.SimpleActionServer(self._action_name,  pkg_commands.msg.FulfillWhseOrderAction, execute_cb=self.execute_cb)
        self._as.start()

    # *** ERROR HAPPENING HERE: ***
        rospy.loginfo('%s: Executing warehouse order' % self._action_name)

    if __name__ == '__main__':
        rospy.init_node('node_ReceiveWhseOrder')
        FulfillWhseOrderAction(rospy.get_name())
        rospy.spin()

---

这将解决问题

对不起，我迷路了。具体在哪里？