Python 3.x Python-数据帧url解析问题
我正在尝试将域名从url从一列转到另一列。它在一个类似字符串的对象上工作,当我应用到dataframe时,它不工作。如何将其应用于数据帧 尝试:Python 3.x Python-数据帧url解析问题,python-3.x,urllib,Python 3.x,Urllib,我正在尝试将域名从url从一列转到另一列。它在一个类似字符串的对象上工作,当我应用到dataframe时,它不工作。如何将其应用于数据帧 尝试: from urllib.parse import urlparse import pandas as pd id1 = [1,2,3] ls = ['https://google.com/tensoflow','https://math.com/some/website',np.NaN] df = pd.DataFrame({'id':id1,'url
from urllib.parse import urlparse
import pandas as pd
id1 = [1,2,3]
ls = ['https://google.com/tensoflow','https://math.com/some/website',np.NaN]
df = pd.DataFrame({'id':id1,'url':ls})
df
# urlparse(df['url']) # ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
# df['url'].map(urlparse) # AttributeError: 'float' object has no attribute 'decode'
处理字符串:
string = 'https://google.com/tensoflow'
parsed_uri = urlparse(string)
result = '{uri.scheme}://{uri.netloc}/'.format(uri=parsed_uri)
result
正在查找专栏:
col3
https://google.com/
https://math.com/
nan
错误您可以尝试这样的方法 这里我使用了pandas.Series.apply()来解决这个问题 »初始化和导入
>>> from urllib.parse import urlparse
>>> import pandas as pd
>>> id1 = [1,2,3]
>>> import numpy as np
>>> ls = ['https://google.com/tensoflow','https://math.com/some/website',np.NaN]
>>> ls
['https://google.com/tensoflow', 'https://math.com/some/website', nan]
>>>
»检查新创建的数据帧
>>> df = pd.DataFrame({'id':id1,'url':ls})
>>> df
id url
0 1 https://google.com/tensoflow
1 2 https://math.com/some/website
2 3 NaN
>>>
>>> df["url"]
0 https://google.com/tensoflow
1 https://math.com/some/website
2 NaN
Name: url, dtype: object
>>>
»使用url列上的pandas.Series.apply(func)
应用函数
»将上述结果存储在变量中(不是强制性的,只是为了简单起见)
»最后
>>> df2 = pd.DataFrame({"col3": s})
>>> df2
col3
0 https://google.com/
1 https://math.com/
2 nan
>>>
»为确保什么是s
和什么是df2
,请检查类型(同样,不是强制性的)
>类型
>>>
>>>
>>>类型(df2)
>>>
参考链接:
>>> s = df["url"].apply(lambda url: "{uri.scheme}://{uri.netloc}/".format(uri=urlparse(url)) if not pd.isna(url) else str(np.nan))
>>> s
0 https://google.com/
1 https://math.com/
2 nan
Name: url, dtype: object
>>>
>>> df2 = pd.DataFrame({"col3": s})
>>> df2
col3
0 https://google.com/
1 https://math.com/
2 nan
>>>