Python 3.x 有没有办法维持字典值的顺序？

下面是我从元组列表中查找不同站点和不同名称的代码：

from collections import defaultdict,OrderedDict
weblogs = [
     ('Nanda', 'google.com'), ('Maha', 'google.com'), 
     ('Fei', 'python.org'), ('Maha', 'google.com'), 
     ('Fei', 'python.org'), ('Nanda', 'python.org'), 
     ('Fei', 'dzone.com'), ('Nanda', 'google.com'), 
     ('Maha', 'google.com'), ]
web = [t for t in (set(tuple(i) for i in weblogs))]
res = defaultdict(list)
for i, j in web:
    res[j].append(i)

a = OrderedDict()
a = dict(res)
for i,j in sorted(a.items()):
    print(i,j)

其输出在以下两个输出之间不断变化：

dzone.com ['Fei']
google.com ['Maha', 'Nanda']
python.org ['Nanda', 'Fei']

dzone.com ['Fei']
google.com ['Nanda', 'Maha']
python.org ['Fei', 'Nanda']

---

有没有办法保持值的恒定顺序？

问题来自集合中值的顺序。一个简单的解决方案是改变这一行：

web = [t for t in (set(tuple(i) for i in weblogs))]

像这样：

web = [t for t in (sorted(set(tuple(i) for i in weblogs)))]