Python 3.x 用请求替换urllib2模块

我正在尝试获取stocks live数据，并使用python绘制与之对应的图表。
在一个教程中，我了解到他们使用的是

urllib2

，我通过堆栈溢出了解到，它由于问题而被挂起，最好的替代方法是

请求

下面是使用

urllib2

的代码段。请为我推荐

请求的确切替代方案

：

    def GetQuote(self, symbols=['AAPL','GOOG']):
    '''This method gets a real-time stock quote from the nasdaq website.'''

    # Make sure the quoteList is a list
    if type(symbols) != type([]):
        symbols = [symbols]

    # Create a string with the list of symbols
    symbolList = ','.join(symbols)

    # Create the full query
    url = self.kBaseURI % symbolList

    # Make sure the URL is formatted correctly
    self.url = urllib2.quote(url, safe="%/:=&?~#+!$,;'@()*[]")

    # Retrieve the data
    urlFile = urllib2.urlopen(self.url)
    self.urlData = urlFile.read()
    urlFile.close()

    # Parse the returned data
    quotes = self._ParseData(self.urlData)

    return quotes

---

您还没有给出完整的代码，但是无论我解释什么，我都会转换它。只有一两行需要更改。代码是用Python 3编写的。确保导入

请求

def GetQuote(self, symbols=['AAPL','GOOG']):
        '''This method gets a real-time stock quote from the nasdaq website.'''

        # Make sure the quoteList is a list
        if type(symbols) != type([]):
            symbols = [symbols]

        # Create a string with the list of symbols
        symbolList = ','.join(symbols)

        # Create the full query
        url = self.kBaseURI % symbolList

        # Make sure the URL is formatted correctly
        self.url = requests.utils.requote_uri(url)

        # Retrieve the data
        urlFile = requests.get(self.url)
        self.urlData = urlFile.content

        # Parse the returned data
        quotes = self._ParseData(self.urlData)

        return quotes