Python 3.x 如何修复'；缩进错误：应为缩进块'；用python

我发现缩进错误

缩进错误：在审核日第33行应出现缩进块= 周2[“日历.星期一”]

这是代码，错误在最后一行，我使用的是最新的python3.7版本

# The calendar can give info based on local such a names of days and months (full and abbreviated forms)
for name in calendar.month_name:
    print(name)
for day in calendar.day_name:
    print(day)
# calculate days based on a rule: For instance an audit day on the second Monday of every month
# Figure out what days that would be for each month, we can use the script as shown here
for month in range(1, 13):
    # It retrieves a list of weeks that represent the month
    mycal = calendar.monthcalendar(2025, month)
    # The first MONDAY has to be within the first two weeks
    week1 = mycal[1]
    week2 = mycal[2]
    if week1[calendar.MONDAY] != 0:
        auditday = week1['calendar.MONDAY']
    else:
    # if the first MONDAY isn't in the first week, it must be in the second week
    auditday = week2['calendar.MONDAY']
print("%10s %2d" % (calendar.month_name[month], auditday))

---

您在上一节中错过了一个缩进块

else:
    # if the first MONDAY isn't in the first week, it must be in the second week
    auditday = week2['calendar.MONDAY']

所以整个代码看起来像

for name in calendar.month_name:
    print(name)
for day in calendar.day_name:
    print(day)
# calculate days based on a rule: For instance an audit day on the second Monday of every month
# Figure out what days that would be for each month, we can use the script as shown here
for month in range(1, 13):
    # It retrieves a list of weeks that represent the month
    mycal = calendar.monthcalendar(2025, month)
    # The first MONDAY has to be within the first two weeks
    week1 = mycal[1]
    week2 = mycal[2]
    if week1[calendar.MONDAY] != 0:
        auditday = week1['calendar.MONDAY']
    else:
    # if the first MONDAY isn't in the first week, it must be in the second week
        auditday = week2['calendar.MONDAY']
print("%10s %2d" % (calendar.month_name[month], auditday))

---

从下一次开始，尝试使用Python的IDE，如PyCharm，它将突出显示缩进错误的语法，如if循环，else循环也应缩进四个空格

if week1[calendar.MONDAY] != 0:
    auditday = week1['calendar.MONDAY']
else:
# if the first MONDAY isn't in the first week, it must be in the second week
    auditday = week2['calendar.MONDAY']

---

谢谢

python非常有帮助地指出-缩进行-它应该与第30行对齐（如果语句后的那一行），您需要更正

之后最后一条语句的缩进，否则

，请检查下面我的答案！您可能需要改写您的答案-循环可能不是描述条件语句的正确词语