Python 3.x 删除逗号并取消列出数据帧

背景

我有以下示例

df

：

import pandas as pd
df = pd.DataFrame({'Before' : [['there, are, many, different'], 
                               ['i, like, a, lot, of, sports '], 
                               ['the, middle, east, has, many']], 
                   'After' : [['in, the, bright, blue, box'], 
                               ['because, they, go, really, fast'], 
                               ['to, ride, and, have, fun'] ],

                  'P_ID': [1,2,3], 
                  'Word' : ['crayons', 'cars', 'camels'],
                  'N_ID' : ['A1', 'A2', 'A3']

                 })

输出

      After                          Before                       N_ID  P_ID  Word
0 [in, the, bright, blue, box]    [there, are, many, different]     A1  1   crayons
1 [because, they, go, really,fast] [i, like, a, lot, of, sports ]   A2  2   cars
2 [to, ride, and, have, fun]        [the, middle, east, has, many]  A3  3   camels

      After                          Before               N_ID  P_ID  Word
0 in the bright blue box        there are many different  A1    1   crayons
1 because they go really fast   i like a lot of sports    A2    2   cars
2 to ride and have fun         the middle east has many   A3    3   camels

所需输出

      After                          Before                       N_ID  P_ID  Word
0 [in, the, bright, blue, box]    [there, are, many, different]     A1  1   crayons
1 [because, they, go, really,fast] [i, like, a, lot, of, sports ]   A2  2   cars
2 [to, ride, and, have, fun]        [the, middle, east, has, many]  A3  3   camels

      After                          Before               N_ID  P_ID  Word
0 in the bright blue box        there are many different  A1    1   crayons
1 because they go really fast   i like a lot of sports    A2    2   cars
2 to ride and have fun         the middle east has many   A3    3   camels

问题

如何获得所需的输出，即1）未列出和2）删除逗号了吗

---

我试着没有用

正如你所确认的，解决方案很简单。对于一列：

df.After.str[0].str.replace(',', '')

Out[2821]:
0         in the bright blue box
1    because they go really fast
2           to ride and have fun
Name: After, dtype: object

对于具有列表的所有列，您需要使用

apply

并按如下方式重新分配：

df.loc[:, ['After', 'Before']] = df[['After', 'Before']].apply(lambda x: x.str[0].str.replace(',', ''))


Out[2824]:
                         After                    Before N_ID  P_ID     Word
0       in the bright blue box  there are many different   A1     1  crayons
1  because they go really fast   i like a lot of sports    A2     2     cars
2         to ride and have fun  the middle east has many   A3     3   camels

---

是否每个单元格都只有一个列表，其中包含一个带逗号的字符串？是的，这是正确的。但仅适用于

后

和

前

列。在这种情况下，它比您链接的列更简单。检查我的答案哈！列之后的

的前10行已经是单个字符串。根本没有清单。如果没有更多的数据正确地表示您所描述的内容，我就无法理解。你能不能编辑这篇文章，从你的真实数据中添加更多的样本，比如
df[['After'，'Before']]的输出。我刚刚检查了值。在那个问题上你已经得到了一些很好的答案。这些答案对你很有用！