Python 3.x 具有嵌套for循环条件的Python切片
我有这样一个数据帧:Python 3.x 具有嵌套for循环条件的Python切片,python-3.x,pandas,slice,Python 3.x,Pandas,Slice,我有这样一个数据帧: df = pd.DataFrame({'A':[1,2,3], 'B':[4,5,6],'C':[7,8,9],'D':[10,11,12]}) x = [1,4] x = [2,5,8] 还有一个列表,这里是x,其长度可能如下所示: df = pd.DataFrame({'A':[1,2,3], 'B':[4,5,6],'C':[7,8,9],'D':[10,11,12]}) x = [1,4] x = [2,5,8] 我想根据x中的值对df进行切片,如下所示 i
df = pd.DataFrame({'A':[1,2,3], 'B':[4,5,6],'C':[7,8,9],'D':[10,11,12]})
x = [1,4]
x = [2,5,8]
还有一个列表,这里是x,其长度可能如下所示:
df = pd.DataFrame({'A':[1,2,3], 'B':[4,5,6],'C':[7,8,9],'D':[10,11,12]})
x = [1,4]
x = [2,5,8]
我想根据x中的值对df进行切片,如下所示
if len(x) == 1:
df[df['A'] == x[0]]
elif len(x) == 2:
df[(df['A'] == x[0]) & (df['B'] == x[1])]
elif len(x) == 3:
df[(df['A'] == x[0]) & (df['B'] == x[1]) & (df['C'] == x[2])]
您知道下面这样的嵌套for循环的更好的解决方案吗
df[(df.iloc[:,i] == x[i]) for i in range(len(x))]
谢谢大家 试试看:
def list_slice(df,x):
return df[df.iloc[:, :len(x)].eq(x).all(1)]
list_slice(df, [1,4])
# A B C D
# 0 1 4 7 10
list_slice(df, [2,5,8])
# A B C D
# 1 2 5 8 11
尝试: