Python 如何迭代对象列表
我有一个物品清单。我想检查一些字符串,如果该字符串作为字段值存在于列表中的任何对象中。比如说,Python 如何迭代对象列表,python,loops,object,Python,Loops,Object,我有一个物品清单。我想检查一些字符串,如果该字符串作为字段值存在于列表中的任何对象中。比如说, class Ani: name = '' def __init__(self, name): self.name = name def getName(self): return self.name animal1 = Ani('alica') animal2 = Ani('rex') animal3 = Ani('bobik') anim
class Ani:
name = ''
def __init__(self, name):
self.name = name
def getName(self):
return self.name
animal1 = Ani('alica')
animal2 = Ani('rex')
animal3 = Ani('bobik')
animal4 = Ani('dobik')
animal5 = Ani('sobik')
a = [animal1, animal2, animal3,animal4,animal5]
我的问题是编写代码以查看是否存在具有给定名称的对象。例如“chip”。您可以迭代对象数组,并使用每个对象的
getName
函数进行检查
class Ani:
name = ''
def __init__(self, name):
self.name = name
def getName(self):
return self.name
animal1 = Ani('alica')
animal2 = Ani('rex')
animal3 = Ani('bobik')
animal4 = Ani('dobik')
animal5 = Ani('sobik')
animals = [animal1, animal2, animal3,animal4,animal5]
searched_animal = 'rex'
for animal in animals:
if animal.getName() == searched_animal:
print('Found')
break
您可以使用
any
加上理解:
any(animal.getName() == "chip" for animal in animals)
对于此程序,您可以使用
Ani
类中的getName
方法
class Ani:
name = ''
def __init__(self, name):
self.name = name
def getName(self):
return self.name
animal1 = Ani('alica')
animal2 = Ani('rex')
animal3 = Ani('bobik')
animal4 = Ani('dobik')
animal5 = Ani('sobik')
animals = [animal1, animal2, animal3,animal4,animal5]
key = 'chip'
flag=0
for animal in animals:
if animal.getName() == key:
print('Found')
flag=1
break
if flag==0:
print("Not Found")
迭代包含任何内容的列表非常简单。像这样:
animal_to_find = "someAnimal"
for animal in animals:
if animal.getName() == animal_to_find:
print("Found a match for: " + animal)
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