Python 与#x27相反'；带参数'；(1L,)和"x27 ;；和关键字参数'；{}'；找不到

我是Django的新手，面临着下一个问题：当我打开适当的链接时，我会遇到下一个错误：

NoReverseMatch at/tutorial/

找不到参数为“（1L，）”且关键字参数为“{}”的“tutorial.views.section_tutorial”的相反版本。

我做错了什么？为什么在参数中传递的是“1L”而不是“1”？（当我返回“1”时，我得到了相同的错误。）我试图更改模板中

'section-detail'

的

'tutorial.views.section\u tutorial'

，但仍然没有任何更改。使用django 1.5.4、python 2.7；谢谢

教程/view.py

：

def get_xhtml(s_url):
    ...
    return result

def section_tutorial(request, section_id):
    sections = Section.objects.all()
    subsections = Subsection.objects.all()
    s_url = Section.objects.get(id=section_id).content
    result = get_xhtml(s_url) 
    return render(request, 'tutorial/section.html', {'sections': sections,
                                                     'subsections': subsections,
                                                     'result': result})

from django.conf.urls import patterns, url
import views

urlpatterns = patterns('',
    url(r'^$', views.main_tutorial, name='tutorial'),
    url(r'^(?P<section_id>\d+)/$', views.section_tutorial, name='section-detail'),
    url(r'^(?P<section_id>\d+)/(?P<subsection_id>\d+)/$', views.subsection_tutorial, name='subsection-detail'),
)

urlpatterns = patterns('',
    url(r'^$', views.index, name='index'),
    url(r'^tutorial/$', include('apps.tutorial.urls')),
)

教程/url.py

：

def get_xhtml(s_url):
    ...
    return result

def section_tutorial(request, section_id):
    sections = Section.objects.all()
    subsections = Subsection.objects.all()
    s_url = Section.objects.get(id=section_id).content
    result = get_xhtml(s_url) 
    return render(request, 'tutorial/section.html', {'sections': sections,
                                                     'subsections': subsections,
                                                     'result': result})

from django.conf.urls import patterns, url
import views

urlpatterns = patterns('',
    url(r'^$', views.main_tutorial, name='tutorial'),
    url(r'^(?P<section_id>\d+)/$', views.section_tutorial, name='section-detail'),
    url(r'^(?P<section_id>\d+)/(?P<subsection_id>\d+)/$', views.subsection_tutorial, name='subsection-detail'),
)

urlpatterns = patterns('',
    url(r'^$', views.index, name='index'),
    url(r'^tutorial/$', include('apps.tutorial.urls')),
)

main.html

：

{% extends "index.html" %} 
{% block content %}
<div class="span2" data-spy="affix">
  <ul id="menu">
    {% for section in sections %}
    <li>
      <a href="{% url 'tutorial.views.section_tutorial' section.id %}">{{ section.name }}</a>
      <ul>
        {% for subsection in subsections%}
        {% if subsection.section == section.id %}
        <li><a href=#>{{ subsection.name }}</a></li>
        {% endif %}
        {% endfor %}
      </ul>
      {% endfor %}
    </li>
  </ul>
</div>
<div class="span9">
    <div class="well">
    {% autoescape off%}
    {{ result }}
    {% endautoescape %}

</div>
</div>

{% endblock %}

{%extends“index.html”%}
{%block content%}

{第%节中的第%节}


{%子节中的子节%}
{%if subsection.section==section.id%}

{%endif%}
{%endfor%}

{%endfor%}


{%autoescape off%}
{{result}}
{%endautoescape%}
{%endblock%}

当包含应用程序url时，在主url文件的url regex中不需要

$

标识符：

url(r'^tutorial/$', include('apps.tutorial.urls')),

应该是：

url(r'^tutorial/', include('apps.tutorial.urls')),

---

我花了30分钟想弄明白，这救了我一命！那么像这样的正则表达式到底是做什么的呢<代码>url（r'^'，包括（'list.url'），