若列表中并没有键和值对，那个么使用python跳过此数据

我有一个包含键和值数据的数据列表，但有时它只包含数据。我想跳过这类数据

我得到以下错误：-

例如：-

formatted_desc_split = ['Akshay Godase is from pune', 'Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']

for each_split_data in formatted_desc_split:
    split_by_colon = each_split_data.split(":")

我想跳过Akshay Godase来自pune的数据。若列表中并没有键和值对，那个么我想跳过这个数据。我无法拆分此数据，因为在第一个索引中没有键值对

---

如何解决上述问题？

请使用以下方法：

formatted_desc_split = ['Akshay Godase is from pune', 'Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']

for each_split_data in formatted_desc_split:
    if ":" not in each_split_data:
        ...

---

请改用以下方法：

formatted_desc_split = ['Akshay Godase is from pune', 'Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']

for each_split_data in formatted_desc_split:
    if ":" not in each_split_data:
        ...

---

这可能不是一种优雅的方式，但是下面的代码可以满足您的需要。只是为了另一种解决方案

formatted_desc_split = ['Akshay Godase is from pune', 'Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']

my_dict = {}

for each_split_data in formatted_desc_split:
    split_by_colon = each_split_data.split(":")
    if len(split_by_colon) == 2:
        my_dict[split_by_colon[0]] = split_by_colon[1]
    print(my_dict)

---

这可能不是一种优雅的方式，但是下面的代码可以满足您的需要。只是为了另一种解决方案

formatted_desc_split = ['Akshay Godase is from pune', 'Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']

my_dict = {}

for each_split_data in formatted_desc_split:
    split_by_colon = each_split_data.split(":")
    if len(split_by_colon) == 2:
        my_dict[split_by_colon[0]] = split_by_colon[1]
    print(my_dict)

---

使用列表理解。简明易读，通俗易懂：

>>> strings = ['Akshay Godase is from pune', 'Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']
>>> [s for s in strings if ':' in s]
['Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']

---

使用列表理解。简明易读，通俗易懂：

>>> strings = ['Akshay Godase is from pune', 'Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']
>>> [s for s in strings if ':' in s]
['Amar:Satara', 'Sandesh:Solapur', 'Mahesh:Nagpur', 'Prashant:Indapur']