如何在python中重命名文本文件？

我有100个文本文件，我想按顺序重命名文件

my text files looks like this 

note 1.txt, note 6.txt,note 15.txt,note 24.txt

---

使用

os

和

re

模块

Ex:

import os
import re
path = "Your Path"

for num, file in enumerate(sorted(os.listdir(path), key=lambda x: int(re.search(r"(\d+)", x).group(1))), 1):
    if not re.search(r"\b{}\.txt".format(num), file):
        print("Rename", file, num)
        os.rename(os.path.join(path, file), os.path.join(path, re.sub(r"\d+", str(num), file)))
    else:
        print("Good", file, num)

---

什么代码试图重命名这些文件@Krishna@MonisMajeed我对snames:s_num=os.path.splitext（file）[0].split（）[1]lst_num=[1,6,8,12,25,28,41,47,71,72,84,86,90,94,97]中的文件使用了相同的代码

code snames=glob（“Note*.txt”），如果lst_num中的int（s_num）：对于lst_num中的i:indx=lst_num.index（i）++1 print（indx）dst=“Note”+str（i）+“.txt”src=文件os.rename（src，dst）

i'm facing an issue like this 

Cannot create a file when that file already exists: 'note 1.txt' -> 'note 6.txt'

it should come in order  of 1,2,3....

import os
import re
path = "Your Path"

for num, file in enumerate(sorted(os.listdir(path), key=lambda x: int(re.search(r"(\d+)", x).group(1))), 1):
    if not re.search(r"\b{}\.txt".format(num), file):
        print("Rename", file, num)
        os.rename(os.path.join(path, file), os.path.join(path, re.sub(r"\d+", str(num), file)))
    else:
        print("Good", file, num)