Python 在烧瓶中,我如何使用横档?
我一直在努力用flask实现用户注册func。这是我完成的代码Python 在烧瓶中,我如何使用横档?,python,flask,Python,Flask,我一直在努力用flask实现用户注册func。这是我完成的代码 import os from flask import Flask, render_template, flash, request, url_for, redirect, session from content_management import Content from dbconnect import connection from wtforms import Form, BooleanField, TextField,
import os
from flask import Flask, render_template, flash, request, url_for, redirect, session
from content_management import Content
from dbconnect import connection
from wtforms import Form, BooleanField, TextField, PasswordField, validators
from passlib.handlers.sha2_crypt import sha256_crypt
from MySQLdb import escape_string as thwart
import gc
def register_page():
try:
form = RegistrationForm(request.form)
if request.method == "POST" and form.validate():
username = form.username.data
email = form.email.data
password = sha256_crypt.encrypt((str(form.password.data)))
c, conn = connection()
x = c.execute("SELECT * FROM users WHERE username = (%s)", (thwart(username)))
if int(x) > 0:
flash("That username is already taken, please choose another")
return render_template("register.html", form = form)
else:
c.execute("INSERT INTO users (username, email, password, tracking) VALUES (%s, %s, %s, %s)", (thwart(username), thwart(password), thwart(email), thwart("/introduction-to-python-programming/")))
conn.commit()
flash("Thanks for registering")
c.close()
conn.close()
gc.collect()
session['login_in'] = True
session['username'] = username
return redirect(url_for('dashboard'))
return render_template("register.html", form = form)
except Exception as e:
return(str(e))
当我填写表单并点击submit按钮时,出现如下错误
并非所有参数都在字符串格式化期间转换
我想这是因为阻碍了。
当我插入print(thwart(username))
时,输出b'username'
x = c.execute("SELECT * FROM users WHERE username = (%s)", (thwart(username)))
但是没有int(x)的值
x = c.execute("SELECT * FROM users WHERE username = (%s)", (thwart(username)))
由于(thwart(username))
,我不确定上述方法是否有效
您能告诉我如何修复它吗?要用项目表示元组,右括号前应该有一个尾随逗号:
>>> x = (1) # without trailing command => `(1) == 1`
>>> type(x)
<type 'int'>
>>> x = (1,) # with trailing comma
>>> type(x)
<type 'tuple'>
或者您可以使用以下列表:
x = c.execute("SELECT * FROM users WHERE username = (%s)", [thwart(username)])
旁注
根据,未定义返回值。最好使用
cursor.fetch*()
来获取结果。要用项目表示元组,右括号前应该有一个尾随逗号:
>>> x = (1) # without trailing command => `(1) == 1`
>>> type(x)
<type 'int'>
>>> x = (1,) # with trailing comma
>>> type(x)
<type 'tuple'>
或者您可以使用以下列表:
x = c.execute("SELECT * FROM users WHERE username = (%s)", [thwart(username)])
旁注
根据,未定义返回值。您最好使用
cursor.fetch*()
来获取结果。非常感谢。当我像上面那样修改代码时,它工作得很好。我对你感激不尽。我还是有点模糊。它们之间的区别是什么?@YuiryKozlenko,(1)
不是一个以1
作为其项的元组,而是一个1
。换言之,(1)==1
@YuiryKozlenko,如果您仍然不清楚tuple literal,请阅读关于感谢一百万的文档。当我像上面那样修改代码时,它工作得很好。我对你感激不尽。我还是有点模糊。它们之间的区别是什么?@YuiryKozlenko,(1)
不是一个以1
作为其项的元组,而是一个1
。换句话说,(1)==1
@YuiryKozlenko,如果您仍然不清楚tuple literal,请阅读有关的文档