Python3:如何创建同一类的不同对象的dict?
我想创建一个dict,它包含同一类的几个对象。每个对象必须是独立的。 比如:Python3:如何创建同一类的不同对象的dict?,python,python-3.x,Python,Python 3.x,我想创建一个dict,它包含同一类的几个对象。每个对象必须是独立的。 比如: #!/usr/bin/python3 class myReserve(): myList = dict() def __init__(self, initName): self.myName = initName self.setList() def setList(self): if self.myName == "fruit":
#!/usr/bin/python3
class myReserve():
myList = dict()
def __init__(self, initName):
self.myName = initName
self.setList()
def setList(self):
if self.myName == "fruit":
self.myList[0] = "Orange"
self.myList[1] = "Lemon"
elif self.myName == "vegetable":
self.myList[0] = "Tomato"
self.myList[1] = "Carrot"
#If neither fruit nor vegetable
#myList should be empty.
myStore = dict()
myStore[0] = myReserve("fruit")
myStore[1] = myReserve("vegetable")
myStore[2] = myReserve("spices")
print(myStore[0].myList)
这张照片是:
{0: 'Tomato', 1: 'Carrot'}
我以为它会打印:
{0: 'Orange', 1: 'Lemon'}
我知道在Python中对象是通过引用传递的
dict1 = {"var": 128}
dict2 = dict1
dict2["var"] = 0
print(dict1["var"])
将打印:
0
通过创建一个类,我想为不同的对象创建一个结构。我不理解第一个代码示例的行为。是否可以用Python的方式执行类似的操作?您的问题是在类级别定义
myList
,这样它就被myReserve
的每个实例共享。请尝试在myReserve.\uuuu init\uuuu
中定义它:
class myReserve():
def __init__(self, initName):
self.myList = dict()
完整代码:
#!/usr/bin/python3
class myReserve():
def __init__(self, initName):
self.myList = dict()
self.myName = initName
self.setList()
def setList(self):
if self.myName == "fruit":
self.myList[0] = "Orange"
self.myList[1] = "Lemon"
elif self.myName == "vegetable":
self.myList[0] = "Tomato"
self.myList[1] = "Carrot"
#If neither fruit nor vegetable
#myList should be empty.
myStore = dict()
myStore[0] = myReserve("fruit")
myStore[1] = myReserve("vegetable")
myStore[2] = myReserve("spices")
print(myStore[0].myList)