Python 如何在Django 1.11.2中自动创建组
我尝试遵循本教程“”，我的代码是：Python 如何在Django 1.11.2中自动创建组,python,django,Python,Django,我尝试遵循本教程“”，我的代码是： # -*- coding: utf-8 -*- # Generated by Django 1.11.2 on 2017-10-16 13:48 from __future__ import unicode_literals from django.db import migrations, models from django.contrib.auth.models import Group, Permission from django.contrib.
# -*- coding: utf-8 -*-
# Generated by Django 1.11.2 on 2017-10-16 13:48
from __future__ import unicode_literals
from django.db import migrations, models
from django.contrib.auth.models import Group, Permission
from django.contrib.auth.management import create_permissions
def add_group_permissions(apps, schema_editor):
for app_config in apps.get_app_configs():
create_permissions(app_config, apps=apps, verbosity=0)
# Criando Administrador
group, created = Group.objects.get_or_create(name='Administrador')
if created:
add_thing = Permission.objects.get(
codename=['can_add_permision',
'can_change_permission',
'can_add_user',
'can_change_user',
'can_add_video',
'can_change_video',
'can_delete_video',
'can_add_documents',
'can_change_documents',
'can_delete_documents',
'can_add_news',
'can_change_news',
'can_delete_news',
'can_add_basics',
'can_change_basics',
'can_add_board',
'can_change_board',
'can_delete_board',
'can_add_history',
'can_change_history',
'can_delete_history',
'can_add_shortcuts',
'can_change_shortcuts',
'can_delete_shortcuts',]
)
group.permissions.add(add_thing)
group.save()
logger.info('Grupo Administrador Criado')
class Migration(migrations.Migration):
dependencies = [
]
operations = [
migrations.RunPython(add_group_permissions),
]
self.model._meta.object_name django.contrib.auth.models.DoesNotExist: Permission matching query does not exist.
依赖关系相关？或者我怎么做
[更新1]
在@Trilliput提示之后，该组被创建为空
[更新2]
在使用了@Trilliput的技巧之后，我删除了前缀can
，使用了shellpython manage.py shell
from django.contrib.auth.models import Permission
permissions_qs = Permission.objects.filter(codename__in=['add_permission', 'change_permission', 'add_user', 'change_user', 'add_video', 'change_video', 'delete_video', 'add_documents', 'change_documents', 'delete_documents', 'add_news', 'change_news', 'delete_news', 'add_basics', 'change_basics', 'add_board', 'change_board', 'delete_board', 'add_history', 'change_history', 'delete_history', 'add_shortcuts', 'change_shortcuts', 'delete_shortcuts',])
permissions_qs.count()
>>> 24
我保存了文件0001.initial.py
并运行了python manage.py migrate
，但什么也没做
我怎么又强迫自己跑了
[更新3]
完整的代码，并且工作得很好
# -*- coding: utf-8 -*-
# Generated by Django 1.11.2 on 2017-10-16 13:48
from __future__ import unicode_literals
from django.db import migrations, models
from django.contrib.auth.models import Group, Permission
from django.contrib.auth.management import create_permissions
def add_group_permissions(apps, schema_editor):
for app_config in apps.get_app_configs():
create_permissions(app_config, apps=apps, verbosity=0)
# Criando Administrador
group, created = Group.objects.get_or_create(name='Administrador')
if created:
permissions_qs = Permission.objects.filter(
codename__in=['add_permission',
'change_permission',
'add_user',
'change_user',
'add_video',
'change_video',
'delete_video',
'add_documents',
'change_documents',
'delete_documents',
'add_news',
'change_news',
'delete_news',
'add_basics',
'change_basics',
'add_board',
'change_board',
'delete_board',
'add_history',
'change_history',
'delete_history',
'add_shortcuts',
'change_shortcuts',
'delete_shortcuts',]
)
group.permissions = permissions_qs
group.save()
class Migration(migrations.Migration):
dependencies = [
('cursos', '0001_initial')
]
operations = [
migrations.RunPython(add_group_permissions),
]
更新代码后，我运行了一个提示@Trilliput:
manage.py迁移登录零-假
- 删除组
manage.py迁移登录
我假设您的新组必须拥有所有权限。您的查询是错误的：
add_thing = Permission.objects.get(
codename=['can_add_permision',
...
'can_delete_shortcuts',]
)
使用objects.get
您请求的权限中，代码名等于给定的列表，这是不可能的，因为代码名是一个字符串。您需要中的请求权限.objects.filter（codename\u\u IN=['can\u add\u Permission'，…]）
。而不是group.permissions.add（添加东西）
您可能需要使用group.permissions=qs
。但请注意，权限将被覆盖。以下是完整的代码：
# -*- coding: utf-8 -*-
# Generated by Django 1.11.2 on 2017-10-16 13:48
from __future__ import unicode_literals
from django.db import migrations, models
from django.contrib.auth.models import Group, Permission
from django.contrib.auth.management import create_permissions
def add_group_permissions(apps, schema_editor):
for app_config in apps.get_app_configs():
create_permissions(app_config, apps=apps, verbosity=0)
# Criando Administrador
group, created = Group.objects.get_or_create(name='Administrador')
if created:
permissions_qs = Permission.objects.filter(
codename__in=['can_add_permision',
'can_change_permission',
'can_add_user',
'can_change_user',
'can_add_video',
'can_change_video',
'can_delete_video',
'can_add_documents',
'can_change_documents',
'can_delete_documents',
'can_add_news',
'can_change_news',
'can_delete_news',
'can_add_basics',
'can_change_basics',
'can_add_board',
'can_change_board',
'can_delete_board',
'can_add_history',
'can_change_history',
'can_delete_history',
'can_add_shortcuts',
'can_change_shortcuts',
'can_delete_shortcuts',]
)
group.permissions = permissions_qs
group.save()
logger.info('Grupo Administrador Criado')
class Migration(migrations.Migration):
dependencies = [
]
operations = [
migrations.RunPython(add_group_permissions),
]
我假设您的新组必须拥有所有权限。您的查询是错误的：
add_thing = Permission.objects.get(
codename=['can_add_permision',
...
'can_delete_shortcuts',]
)
使用objects.get
您请求的权限中，代码名等于给定的列表，这是不可能的，因为代码名是一个字符串。您需要中的请求权限.objects.filter（codename\u\u IN=['can\u add\u Permission'，…]）
。而不是group.permissions.add（添加东西）
您可能需要使用group.permissions=qs
。但请注意，权限将被覆盖。以下是完整的代码：
# -*- coding: utf-8 -*-
# Generated by Django 1.11.2 on 2017-10-16 13:48
from __future__ import unicode_literals
from django.db import migrations, models
from django.contrib.auth.models import Group, Permission
from django.contrib.auth.management import create_permissions
def add_group_permissions(apps, schema_editor):
for app_config in apps.get_app_configs():
create_permissions(app_config, apps=apps, verbosity=0)
# Criando Administrador
group, created = Group.objects.get_or_create(name='Administrador')
if created:
permissions_qs = Permission.objects.filter(
codename__in=['can_add_permision',
'can_change_permission',
'can_add_user',
'can_change_user',
'can_add_video',
'can_change_video',
'can_delete_video',
'can_add_documents',
'can_change_documents',
'can_delete_documents',
'can_add_news',
'can_change_news',
'can_delete_news',
'can_add_basics',
'can_change_basics',
'can_add_board',
'can_change_board',
'can_delete_board',
'can_add_history',
'can_change_history',
'can_delete_history',
'can_add_shortcuts',
'can_change_shortcuts',
'can_delete_shortcuts',]
)
group.permissions = permissions_qs
group.save()
logger.info('Grupo Administrador Criado')
class Migration(migrations.Migration):
dependencies = [
]
operations = [
migrations.RunPython(add_group_permissions),
]
“部分工作”，因为组为空。谢谢@JulianoAraújo确保您确实拥有所有权限。尝试在Django控制台中调用Permissions.objects.filter（codename\uu in=['can\u add\u permission'，…，'can\u delete\u shortcuts'，]）.count（）
@JulianoAraújo，顺便说一句，如果你想要所有的权限，你可以只使用group.Permissions=Permissions.objects.all（）
这不是所有的权限，是一些。例如，此组不能可以\u删除\u权限
。我将在控制台中尝试查看。我使用了您关于在控制台中尝试的提示。。。我有更新2.Works的结果，因为组是空的。谢谢@JulianoAraújo确保您确实拥有所有权限。尝试在Django控制台中调用Permissions.objects.filter（codename\uu in=['can\u add\u permission'，…，'can\u delete\u shortcuts'，]）.count（）
@JulianoAraújo，顺便说一句，如果你想要所有的权限，你可以只使用group.Permissions=Permissions.objects.all（）
这不是所有的权限，是一些。例如，此组不能可以\u删除\u权限
。我将在控制台中尝试查看。我使用了您关于在控制台中尝试的提示。。。我有更新2的结果。