Python 将变量传递到函数中

这是我的代码，使用三角学来查找三角形上缺少的边。它通过使用SOHCAHTOA找到这些边来工作。 代码的问题是，当我试图运行代码时，调用用户定义的函数：get_方法时，它会给出一个无效的语法。 请告诉我代码有什么问题，以及如何解决我的程序中出现的一致性问题

import math

def get_method(question, method):
    print("Lable the right-angle triangle.")
    question = input("What are you trying to find? Type 'h' for hypotenuse, 'a' for adjacent or 'o' for opposite.").lower().strip()
    method = ""
    if question == "h":
        opposite_verify = input("Do you have the length of the opposite?\n"
                              "Type 'yes' or 'no'").strip().lower()
        if opposite_verify == "yes":
            method = "sine"
        elif opposite_verify == "no":
            adjacent_verify = input("Do you have the length of the adjacent?\n"
                              "Type 'yes' or 'no'").strip().lower()
            if adjacent_verify == "yes":
                method = "cosine"
            else:
                print("There's no way to solve this.")

    elif question == "a":
        hypotenuse_verify = input("Do you have the length of the hypotenuse?\n"
                              "Type 'yes' or 'no'").strip().lower()
        if hypotenuse_verify == "yes":
            method = "cosine"
        elif hypotenuse_verify == "no":
            opposite_verify = input("Do you have the length of the opposite?\n"
                              "Type 'yes' or 'no'").strip().lower()
            if opposite_verify == "yes":
                method = "tan"
            else:
                print("There's no way to solve this.")

    elif question == "o":
        hypotenuse_verify = input("Do you have the length of the hypotenuse?\n"
                              "Type 'yes' or 'no'").strip().lower()
        if hypotenuse_verify == "yes":
            method = "sine"
        elif hypotenuse_verify == "no":
            adjacent_verify = input("Do you have the length of the adjacent?\n"
                              "Type 'yes' or 'no'").strip().lower()
            if adjacent_verify == "yes":
                method = "tan"
            else:
                print("There's no way to solve this.")

    return method, question

def main(question, method):
    angle = float(input("What is the degrees of the angle?"))
    angle /= (math.pi / 180)
    if method == "sine" and question == "h":
        opposite = float(input("What is length of the opposite angle?"))
        hypotenuse = opposite / (math.sin(angle))
        print("The length of the hypotenuse is {}".format(hypotenuse))
    elif method == "sine" and question == "o":
        hypotenuse = float(input("What is the length of the hypotenuse?"))
        opposite = hypotenuse * (math.sin(angle))
        print("The length of the opposite is {}".format(opposite))
    elif method == "cosine" and question == "a":
        hypotenuse = float(input("What is the length of the hypotenuse?"))
        ajacent = hypotenuse * (math.cos(angle))
        print("The length of the ajacent is {}".format(ajacent))
    elif method == "cosine" and question == "h":
        ajacent = float(input("What is the length of the ajacent?"))
        hypotenuse = ajacent / (math.cos(angle))
        print("The length of the hypotenuse is {}".format(hypotenuse))
    elif method == "tan" and question == "o":
        ajacent = float(input("What is the length of the ajacent?"))
        opposite = ajacent * (math.tan(angle))
        print("The length of the opposte is {}".format(opposite))
    elif method == "tan" and question == "a":
        opposite = float(input("What is the length z"))


get_method(question, method)
main(question, method)

正如您可能看到的，我在将变量传递到函数中时遇到了一个问题。是的，我知道我的代码效率很低，但我只是一个新手，所以让我放松一下 我添加了两个助手函数来简化get_方法代码：

现在，您可以通过以下方式进行呼叫：

method, question = get_method()

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如果您遇到异常，请编辑问题以包含完整的异常回溯。不过，有时会在错误的行上报告SyntaxError，因为错误的原因是Python对代码结构的混淆，而这些混淆通常是由于缺少右括号之类的原因造成的。

method, question = get_method()