Python 3.6/Tkinter:找不到文件->；FileNotFoundError:[Errno 2]没有这样的文件或目录：'；XXXX和x27；

我正试图根据SeaofBTCapp（Sentdex）的思想构建一个应用程序，Python/Tkinter没有找到我的“sampleData.csv”文件，尽管我确信我有正确的目录。（我尝试了.csv和.txt扩展，但都没有用。）我希望这个MWE不是太小，显然我导入了tkinter和其他matplotlib模块，据我所知，open（）函数是python的本机函数

功能：

import matplotlib.animation as animation

def animate(i):
    pullData = open('sampleData.csv', "r").read()
    dataList = pullData.split('\n')
    xList =[]
    yList = []
    for eachLine in dataList:
        if len(eachLine)>1:
            x, y = eachLine.split(',')
            xList.append(int(x))
            yList.append(int(y))
    a.clear()
    a.plot(xList, yList )

File "/Users/nrsmoll/PycharmProjects/SeaofStats/main.py", line 27, in animate
    pullData = open('sampleData.csv', "r").read()
FileNotFoundError: [Errno 2] No such file or directory: 'sampleData.csv'

print(os.getcwd())
/Users/nrsmoll/PycharmProjects/SeaofStats
print(os.listdir())
['.DS_Store', 'main.py', 'sampleData.csv', '.idea']
print(os.listdir())
['.DS_Store', 'sampleData.csv', 'main.py', '.idea']
print(os.path.exists(r"sampleData.csv")) 
True

回溯：

import matplotlib.animation as animation

def animate(i):
    pullData = open('sampleData.csv', "r").read()
    dataList = pullData.split('\n')
    xList =[]
    yList = []
    for eachLine in dataList:
        if len(eachLine)>1:
            x, y = eachLine.split(',')
            xList.append(int(x))
            yList.append(int(y))
    a.clear()
    a.plot(xList, yList )

File "/Users/nrsmoll/PycharmProjects/SeaofStats/main.py", line 27, in animate
    pullData = open('sampleData.csv', "r").read()
FileNotFoundError: [Errno 2] No such file or directory: 'sampleData.csv'

print(os.getcwd())
/Users/nrsmoll/PycharmProjects/SeaofStats
print(os.listdir())
['.DS_Store', 'main.py', 'sampleData.csv', '.idea']
print(os.listdir())
['.DS_Store', 'sampleData.csv', 'main.py', '.idea']
print(os.path.exists(r"sampleData.csv")) 
True

文件系统检查：

import matplotlib.animation as animation

def animate(i):
    pullData = open('sampleData.csv', "r").read()
    dataList = pullData.split('\n')
    xList =[]
    yList = []
    for eachLine in dataList:
        if len(eachLine)>1:
            x, y = eachLine.split(',')
            xList.append(int(x))
            yList.append(int(y))
    a.clear()
    a.plot(xList, yList )

File "/Users/nrsmoll/PycharmProjects/SeaofStats/main.py", line 27, in animate
    pullData = open('sampleData.csv', "r").read()
FileNotFoundError: [Errno 2] No such file or directory: 'sampleData.csv'

print(os.getcwd())
/Users/nrsmoll/PycharmProjects/SeaofStats
print(os.listdir())
['.DS_Store', 'main.py', 'sampleData.csv', '.idea']
print(os.listdir())
['.DS_Store', 'sampleData.csv', 'main.py', '.idea']
print(os.path.exists(r"sampleData.csv")) 
True

---

啊，答案是简单地把整个或绝对路径：

pullData = open('/Users/nrsmoll/PycharmProjects/SeaofStats/sampleData.csv', "r").read()

---

这么简单。但是，如果有人知道如何进行调试，这样我就不必在其中放置绝对路径，那就太好了，我想在创建独立项目时可能需要这样做。

谢谢，这是最后一分钟尝试的调试。为了进行调试，您能在打开文件之前将os.getcwd（）和os.listdir（）放在代码中吗？然后，您可以将os.path.join与os.getcwd和filename一起使用。Tkinter内置了一个文件选择器。显示文件选择器，等待用户选择文件，然后获取所选文件的绝对路径。看看这个问题：你不应该把绝对路径。最有可能的是，当前工作目录已更改，或者不是您假定的那样。如果您认为cwd在您认为的位置，那么相对路径应该是有效的。