如何在Python中通过文本获取href链接

这是web html内容的一部分：

<a href="https://www.cnbeta.com/articles/science/1062069.htm"><strong>阅读全文</strong></a>

---

您可能想试试

beautifulsou

例如：

from bs4 import BeautifulSoup

sample_html = """
<a href="https://www.cnbeta.com/articles/science/1062069.htm"><strong>阅读全文</strong></a>
<a href="https://www.cnbeta.com/articles/science/1062068.htm"><strong>RANDOM TEXT!</strong></a>
"""

soup = BeautifulSoup(sample_html, "html.parser").find_all(lambda t: t.name == "a" and t.text.startswith("阅"))

print([a["href"] for a in soup])

---

你有密码吗？如何解析HTML？这是否回答了您的问题？不，它可能会找到所有带有a的标签，我只想找到one@TomerikooThe最简单的方法是循环所有

标记，一旦找到包含此文本的标记，就停止。

from bs4 import BeautifulSoup

sample_html = """
<a href="https://www.cnbeta.com/articles/science/1062069.htm"><strong>阅读全文</strong></a>
<a href="https://www.cnbeta.com/articles/science/1062068.htm"><strong>RANDOM TEXT!</strong></a>
"""

soup = BeautifulSoup(sample_html, "html.parser").find_all(lambda t: t.name == "a" and t.text.startswith("阅"))

print([a["href"] for a in soup])

['https://www.cnbeta.com/articles/science/1062069.htm']