Python 使用纬度和经度计算多个源和目的地之间的距离

我有多个来源和交付地点的数据，以及它们各自的纬度和经度值，我需要计算每个来源和目的地之间的距离（以公里/英里为单位），下面是来源和目的地坐标

原点坐标=[
'-33.8309, 151.0875', 
'-33.77733, 151.119854']
目的地协调=[
'-25.5789375305176, 134.359710693359', 
'-12.46029472, 130.8423157', 
'-33.87905884, 151.2432098']

---

有人能帮我在python中执行它吗？你可以使用

geopy

包：

from geopy.distance import geodesic
for org, dst in zip(origin_coords, destination_coords):
    print(geodesic(org, dst).kilometers)

---

（以公里为单位）：

1855.6690160383962
3131.115522557264

编辑：

1855.6690160383962
3131.115522557264

如果要查找从每个原点到目的地的距离，请使用以下命令：

import itertools 

coord_orig_2_dst = list(itertools.product(origin_coords, destination_coords)) # <-- will give 6 pairs
for idx, (org, dst) in enumerate(coord_orig_2_dst):

    if (idx+1)%(len(origin_coords)):
        print(f"\nposition from origin{(idx+1)//(len(origin_coords))} to destination")
    print(geodesic(org, dst).kilometers)

---

你在找这样的东西

from sklearn.metrics import pairwise_distances
import numpy as np
from math import sin, cos, sqrt, atan2, radians

origin_coords = ['-33.8309, 151.0875', '-33.77733, 151.119854'] 
destination_coords = ['-25.5789375305176, 134.359710693359', '-12.46029472, 130.8423157', '-33.87905884, 151.2432098']

origin_coords = [[float(v.split(",")[0]), float(v.split(",")[1])] for v in origin_coords]
destination_coords = [[float(v.split(",")[0]), float(v.split(",")[1])] for v in destination_coords]

origin_coords = np.array([[radians(v[0]), radians(v[1])] for v in origin_coords])
destination_coords = np.array([[radians(v[0]), radians(v[1])] for v in destination_coords])

# distance in km.
def geodesic_dist(x, y):
  dlon = y[1] - x[1]
  dlat = y[0] - x[0]
  a = sin(dlat / 2)**2 + cos(x[0]) * cos(y[0]) * sin(dlon / 2)**2
  c = 2 * atan2(sqrt(a), sqrt(1 - a))

  return 6373.0 * c

print(pairwise_distances(origin_coords, destination_coords, metric=geodesic_dist))

产生

[[1854.93894877 3138.98807828   15.34816524]
 [1855.11802065 3136.96316526   16.06085592]]

---

有关详细信息，请参阅。

您能分享您迄今为止的尝试吗？选中此项：