Python 如何在与基于类的FormView一起使用的模板中显示当前对象
具有以下URL.py代码段:Python 如何在与基于类的FormView一起使用的模板中显示当前对象,python,django,formview,Python,Django,Formview,具有以下URL.py代码段: url(r'^storageitem/(?P<pk>[\w]+)/addtransaction/$', login_required( StorageItemTransactionAddView.as_view()), name='storage_item_transaction'), 但此时无法访问该方法。所以我想知道怎样才能用正确的方法来做?我所需要的只是 self.object = StorageItem.objects.get
url(r'^storageitem/(?P<pk>[\w]+)/addtransaction/$', login_required(
StorageItemTransactionAddView.as_view()),
name='storage_item_transaction'),
但此时无法访问该方法。所以我想知道怎样才能用正确的方法来做?我所需要的只是
self.object = StorageItem.objects.get(pk='my pk')
您可以覆盖以传递额外的上下文:
...
def get_context_data(self, **kwargs):
context = super(ItemCreate, self).get_context_data(**kwargs)
context['storage_item'] = StorageItem.objects.get(pk=self.kwargs['pk'])
return context
为什么不简单地执行以下操作:
class StorageItemTransactionAddView(View):
def post(self, request, pk):
storage_item = StorageItem.objects.get(pk=pk)
...
return render(request, 'myapp/index.html', {'object': storage_item})
<h1>{{ object.name }}</h1>
现在,在模板中,可以执行以下操作:
class StorageItemTransactionAddView(View):
def post(self, request, pk):
storage_item = StorageItem.objects.get(pk=pk)
...
return render(request, 'myapp/index.html', {'object': storage_item})
<h1>{{ object.name }}</h1>
{{object.name}
希望能有帮助