Python 取消包装或取消继承对象

我无权访问的代码块返回一个对象，该对象是“包装”的，或者更确切地说是从基类继承的，我希望恢复该对象。包装纸是有害的，我想把它扔掉。有没有向上转换到父类的方法？打开物体？剥夺它的继承权

我准备了一个简单的例子：是否有可能操纵

u

对象，使其成为

Person

对象，并友好地打招呼

class Person():
    def __init__(self, name):
        self.name = name

    def say_hello(self):
        print("Hi, my name is " + self.name)

class Unfriendly_Person(Person):
    def say_hello(self):
        print("Leave me alone!")

u = Unfriendly_Person("TJ")
u.say_hello()

---

您可以分配给

\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

class Person():
    def __init__(self, name):
        self.name = name
    def say_hello(self):
        print("Hi, my name is " + self.name)

class Unfriendly_Person(Person):
    def say_hello(self):
        print("Leave me alone!")

u = Unfriendly_Person("TJ")
u.__class__ = Person
u.say_hello()

输出：

Hi, my name is TJ

但是请记住，这将抛弃
Unfriendly\u Person
中的所有方法，即使是
Person
中未定义的方法。超级令人沮丧的是，我一直在用Super关键字寻找解决方案，却没有遇到这种构造。谢谢好双关语；）这将是非常令人沮丧的，很高兴它worked@python_user，把它贴出来作为答案，也许吧？@MatBBastos，这多半是个骗局