Python中的Regex替换为负前瞻

我正在尝试删除规则文本周围的单引号。例如，给定列表：

alist = ["'ABC'", '(-inf-0.5]', '(4800-20800]', "'\\'(4.5-inf)\\''", "'\\'(2.75-3.25]\\''"]

我想将“ABC”改为“ABC”，但保留其他引号，即：

alist = ["ABC", '(-inf-0.5]', '(4800-20800]', "'\\'(4.5-inf)\\''", "'\\'(2.75-3.25]\\''"]

我尝试使用look head，如下所示：

fixRepeatedQuotes = lambda text: re.sub(r'(?<!\\\'?)\'(?!\\)', r'', text)
print [fixRepeatedQuotes(str) for str in alist]

---

还有其他解决办法吗？提前多谢

尝试应该有效：

result = re.sub("""(?s)(?:')([^'"]+)(?:')""", r"\1", subject)

解释

"""
(?:         # Match the regular expression below
   '           # Match the character “'” literally
)
(           # Match the regular expression below and capture its match into backreference number 1
   [^'"]       # Match a single character NOT present in the list “'"”
      +           # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
(?:         # Match the regular expression below
   '           # Match the character “'” literally
)
"""

---

re.sub

接受函数作为替换文本。所以,

re.sub(r"'([A-Za-z]+)'", lambda match: match.group(), "'ABC'")

屈服

"ABC"

---

你想让

“\\'（4.5-inf）\\''”

产生什么？好的，那么你对“常规文本”的定义是什么？字母数字A-Z？谢谢Joel，它解决了我的问题。应该是match.group（1）。@Eric:我想你把

.group（）

和

groups（）

搞混了。（参考上述评论。）

"ABC"