Python分布式计算(works)
我正在使用一个旧线程发布新代码,试图解决相同的问题。 什么是安全泡菜 短袜Python分布式计算(works),python,sockets,multiprocessing,pickle,distributed-computing,Python,Sockets,Multiprocessing,Pickle,Distributed Computing,我正在使用一个旧线程发布新代码,试图解决相同的问题。 什么是安全泡菜 短袜 from socket import socket from socket import AF_INET from socket import SOCK_STREAM from socket import gethostbyname from socket import gethostname class SocketServer: def __init__(self, port): self.sock =
from socket import socket
from socket import AF_INET
from socket import SOCK_STREAM
from socket import gethostbyname
from socket import gethostname
class SocketServer:
def __init__(self, port):
self.sock = socket(AF_INET, SOCK_STREAM)
self.port = port
def listen(self, data):
self.sock.bind(("127.0.0.1", self.port))
self.sock.listen(len(data))
while data:
s = self.sock.accept()[0]
siz, dat = data.pop()
s.send(siz)
s.send(dat)
s.close()
class Socket:
def __init__(self, host, port):
self.sock = socket(AF_INET, SOCK_STREAM)
self.sock.connect((host, port))
def recv(self, size):
return self.sock.recv(size)
pack.py
#http://stackoverflow.com/questions/6234586/we-need-to-pickle-any-sort-of-callable
from marshal import dumps as marshal_dumps
from pickle import dumps as pickle_dumps
from struct import pack as struct_pack
class packer:
def __init__(self):
self.f = []
def pack(self, what):
if type(what) is type(lambda:None):
self.f = []
self.f.append(marshal_dumps(what.func_code))
self.f.append(pickle_dumps(what.func_name))
self.f.append(pickle_dumps(what.func_defaults))
self.f.append(pickle_dumps(what.func_closure))
self.f = pickle_dumps(self.f)
return (struct_pack('Q', len(self.f)), self.f)
解包
from types import FunctionType
from pickle import loads as pickle_loads
from marshal import loads as marshal_loads
from struct import unpack as struct_unpack
from struct import calcsize
#http://stackoverflow.com/questions/6234586/we-need-to-pickle-any-sort-of-callable
class unpacker:
def __init__(self):
self.f = []
self.fcompiled = lambda:None
self.sizeofsize = calcsize('Q')
def unpack(self, sock):
size = struct_unpack('Q', sock.recv(self.sizeofsize))[0]
self.f = pickle_loads(sock.recv(size))
a = marshal_loads(self.f[0])
b = globals() ##
c = pickle_loads(self.f[1])
d = pickle_loads(self.f[2])
e = pickle_loads(self.f[3])
self.fcompiled = FunctionType(a, b, c, d, e)
return self.fcompiled
test.py
from unpack import unpacker
from pack import packer
from sock import SocketServer
from sock import Socket
from threading import Thread
from time import sleep
count = 2
port = 4446
def f():
print 42
def server():
ss = SocketServer(port)
pack = packer()
functions = [pack.pack(f) for nothing in range(count)]
ss.listen(functions)
if __name__ == "__main__":
Thread(target=server).start()
sleep(1)
unpack = unpacker()
for nothing in range(count):
print unpack.unpack(Socket("127.0.0.1", port))
输出:
<function f at 0x12917d0>
<function f at 0x12915f0>
我不认为流程对象设计为通过网络发送。查看multiprocessing/process.py中的第256行
# We subclass bytes to avoid accidental transmission of auth keys over network.
听起来我有很好的理由。如果您想进行分布式计算,可能应该研究一个。
值错误:当pickle损坏时,会引发不安全的字符串pickle
。您确定要在一个sock.recv()
(unpack.py)中接收整个pickle对象吗
编辑:为了避免这种情况,您可以对任何大小执行(您的Socket
类必须支持recv,以便使用缓冲区大小参数(即
)):
在接收器程序中:
import struct
length = struct.unpack('Q', sock.recv(struct.calcsize('Q')))[0]
pickled_list = sock.recv(length)
“Q”是一个
无符号long
。有关其他struct内容,请参见是否可以发布一些示例代码来测试脚本?谢谢抛出的错误在哪一行?请记住,函数使用的所有全局变量都应该在unpack.py
中重新创建。您不应该比较type(What)is type(lambda:None)
中的类型,而应该是isinstance(What,types.FunctionType)
。我只能使用本机库。我的第一个选择是绕过该安全措施,因为该实现使用的是专用网络。查看文档,似乎多处理
是线程
的克隆,但要跨越不同的进程,以避免全局解释器锁定。我认为你的选择是滚动你自己的分布式计算库,或者让管理层相信开源的重要性非常感谢。缓冲区大小太小。
import struct
struct.pack('Q', len(pickled_list))
# Send it, and then send the pickled list.
import struct
length = struct.unpack('Q', sock.recv(struct.calcsize('Q')))[0]
pickled_list = sock.recv(length)