python从接口将数据插入sqlite 3

所以我用Python3设计了一个基于终端的应用程序，我发现为这个应用程序设计了GUI。我在sqlite3中设计了一个数据库，现在我的问题是，当我点击提交按钮时，我必须从GUI中插入数据到数据库中。基本上我有前端和后端，剩下的是连接

# import Statements
# Used Api Library "ttt"
from tkinter import *
from tkinter import ttk
from tkinter import messagebox

# class is made 
class MovieOrganizer:

    #init method
    def __init__(self, master):    


        # <----- Header Coding starts here -------> 
        self.frame_header = ttk.Frame(master)
        self.frame_header.pack()

        #Importing the picture
        self.logo = PhotoImage(file = 'movie_logo.png')

        # creating the labels in the frame header. 
        ttk.Label(self.frame_header, image = self.logo).grid(row = 0, column = 0, rowspan = 2)
        ttk.Label(self.frame_header, text = 'Welcome to movie organizer!').grid(row = 0, column = 1)
        ttk.Label(self.frame_header, wraplength = 300,
                  text = ("By the application you easily know different category  of movies you want to watch and when to watch.  "
                          "You can also categorize the movies, save the date you watched and find the location of the movie in your systm.")).grid(row = 1, column = 1)



        # <----- Content Coding starts here -------> 
        self.frame_content = ttk.Frame(master)
        self.frame_content.pack()

        # creating the labels in the frame content.

        ttk.Label(self.frame_content, text = 'Movie Name:').grid(row = 0, column = 0, padx = 5, sticky = 'sw')
        ttk.Label(self.frame_content, text = 'Movie category:').grid(row = 0, column = 1, padx = 5, sticky = 'sw')
        ttk.Label(self.frame_content, text = 'Date you watched:').grid(row = 2, column = 0, padx = 5, sticky = 'sw')
        ttk.Label(self.frame_content, text = 'Rate the movie out of 10:').grid(row = 2, column = 1, padx = 5, sticky = 'sw')
        ttk.Label(self.frame_content, text = 'Any Comments on the movie?:').grid(row = 4, column = 0, padx = 5, sticky = 'sw')
        # I need to add more label later on. 


        #input fields for the label created
        #varible is assigned 
        self.entry_name = ttk.Entry(self.frame_content, width = 24)
        self.entry_category = ttk.Entry(self.frame_content, width = 24)
        self.entry_category = ttk.Entry(self.frame_content, width = 24)
        self.entry_date = ttk.Entry(self.frame_content, width = 24)
        self.entry_rate = ttk.Entry(self.frame_content, width = 24)
        #self.check() 
        self.text_comments = Text(self.frame_content, width = 50, height = 10)


        #position setting for the inputs 
        self.entry_name.grid(row = 1, column = 0, padx = 5)
        self.entry_category.grid(row = 1, column = 1, padx = 5)
        self.entry_date.grid(row = 3, column = 0, padx = 5)
        self.entry_rate.grid(row = 3, column = 1, padx = 5)
        self.text_comments.grid(row = 5, column = 0, columnspan = 2, padx = 5)


        #setting the buttons submit button submit form to db and clear clears all the values for a reentery
        # I need to add 2 more button but db connectivity should be there.  One button is a view button I will put a view for all the movies.  And second button is delete the entry 
        ttk.Button(self.frame_content, text = 'Submit', command = self.submit).grid(row = 6, column = 0, padx = 5, pady = 5, sticky = 'e')
        ttk.Button(self.frame_content, text = 'Clear', command = self.clear).grid(row = 6, column = 1, padx = 5, pady = 5, sticky = 'w')
        #ttk.Button(self.frame_content, text = '', command = self.view).grid(row = 6, column = 2, padx = 5, pady = 5, sticky = 'e')



        # an if coditon Want to fix it before next prototype. 
       # def check(self):
        #    if self.entry_rate <10:
         #        messagebox.showinfo(title = 'New Movie Entry ', message = 'Updated!')


         # this method works on submit button    


    def submit(self):
        print('Name: {}'.format(self.entry_name.get()))
        print('Category: {}'.format(self.entry_category.get()))
        print('Date: {}'.format(self.entry_date.get()))
        print('Rate: {}'.format(self.entry_rate.get()))

        print('Comments: {}'.format(self.text_comments.get(1.0, 'end')))
        self.clear()

        messagebox.showinfo(title = 'New Movie Entry ', message = 'Updated!')



    def clear(self):
        self.entry_name.delete(0, 'end')
        self.entry_category.delete(0, 'end')
        self.entry_date.delete(0, 'end')
        self.entry_rate.delete(0, 'end')
        self.text_comments.delete(1.0, 'end')
   # def view(self):

def main():            

    root = Tk()
    movieOrganizer = MovieOrganizer(root)
    root.mainloop()

    #if conditiom 
if __name__ == "__main__": main()

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我是一个新手，但是看看你的代码，你在同一页的代码片段中没有得到任何sqlite的连接，如果你得到了它，你可以修复损坏的代码并将每一行附加到它，所以在最后你得到了db和运行的代码

很抱歉为我的数据库添加了代码>>>con sqlite3.connect'hrdb'语法错误：无效语法>>>con=sqlite3.connect'hrdb'>>>键入con>>cur=con.cursor>>>cur.execute'CREATE TABLE moview id integer primary key，Movie varchar50，category vatchar50，date varchar50，rate integer，评论varchar50'你的问题是什么？您遇到的问题是什么？我需要在单击“提交”按钮时从界面输入数据。我已经制作了接口和数据库，但是我不能将接口中的数据输入数据库，这意味着什么？你有错误吗？如果是这样的话，有什么错误？我想指出的是，这篇文章已经停刊近两年了，对上面的评论没有任何回应。祝你好运得到回复，欢迎来到StackOverflow！