如何使用Python绘制组织树图?
我想建立一个组织结构图。如下图所示:如何使用Python绘制组织树图?,python,plot,charts,tree,visualization,Python,Plot,Charts,Tree,Visualization,我想建立一个组织结构图。如下图所示: A - B - C B - C - D A - E 这意味着A管理B,B管理C,C管理D,A管理E。我想知道是否可以将每个员工作为节点来构建树状图 A - B - C - D | E 有些代码如下,我不知道如何将其应用于我当前的人力资源数据 pip install python-igraph import igraph from igraph import Graph, EdgeSeq nr_vertices = 25 v_label = list(m
A - B - C
B - C - D
A - E
这意味着A管理B,B管理C,C管理D,A管理E。我想知道是否可以将每个员工作为节点来构建树状图
A - B - C - D
|
E
有些代码如下,我不知道如何将其应用于我当前的人力资源数据
pip install python-igraph
import igraph
from igraph import Graph, EdgeSeq
nr_vertices = 25
v_label = list(map(str, range(nr_vertices)))
G = Graph.Tree(nr_vertices, 2) # 2 stands for children number
lay = G.layout('rt')
position = {k: lay[k] for k in range(nr_vertices)}
Y = [lay[k][1] for k in range(nr_vertices)]
M = max(Y)
es = EdgeSeq(G) # sequence of edges
E = [e.tuple for e in G.es] # list of edges
L = len(position)
Xn = [position[k][0] for k in range(L)]
Yn = [2*M-position[k][1] for k in range(L)]
Xe = []
Ye = []
for edge in E:
Xe+=[position[edge[0]][0],position[edge[1]][0], None]
Ye+=[2*M-position[edge[0]][1],2*M-position[edge[1]][1], None]
labels = v_label
import plotly.graph_objects as go
fig = go.Figure()
fig.add_trace(go.Scatter(x=Xe,
y=Ye,
mode='lines',
line=dict(color='rgb(210,210,210)', width=4),
hoverinfo='none'
))
fig.add_trace(go.Scatter(x=Xn,
y=Yn,
mode='markers',
name='bla',
marker=dict(symbol='circle-dot',
size=28,
color='#6175c1', #'#DB4551',
line=dict(color='rgb(50,50,50)', width=1)
),
text=labels,
hoverinfo='text',
opacity=0.8
))
def make_annotations(pos, text, font_size=15,
font_color='rgb(250,250,250)'):
L=len(pos)
if len(text)!=L:
raise ValueError('The lists pos and text must have the same len')
annotations = []
for k in range(L):
annotations.append(
dict(
text=labels[k], # or replace labels with a different list for the text within the circle
x=pos[k][0], y=2*M-position[k][1],
xref='x1', yref='y1',
font=dict(color=font_color, size=font_size),
showarrow=False)
)
return annotations
axis = dict(showline=False, # hide axis line, grid, ticklabels and title
zeroline=False,
showgrid=False,
showticklabels=False,
)
fig.update_layout(title= 'Tree with Reingold-Tilford Layout',
annotations=make_annotations(position, v_label),
font_size=12,
showlegend=False,
xaxis=axis,
yaxis=axis,
margin=dict(l=40, r=40, b=85, t=100),
hovermode='closest',
plot_bgcolor='rgb(248,248,248)'
)
fig.show()
我不知道圆圈里的数字是怎么显示的。相反,我希望员工的姓名显示在圆圈中。
有人能帮忙吗