Python 基于FPGA-Uart的Pyserial串行数据传输

我知道这已经被讨论了很多，但是没有找到解决我问题的正确方法。 我正在用FPGA将数据发送到Uart中。 FPGA部分很清楚，我在FPGA ide上使用8位UART接收器\tx。 数据看起来像 000101010101 101010110110 101011001011 . . . . .. 101010110110（即12列数据和4096行ASCII值）

有人能帮我以某种方式将这些数据从pyserial以二进制形式串行发送到Uart吗？？

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先谢谢你

我在使用pyserial时编写的旧代码可能有用：

class myser():
    timer = ''
    buffer = b''
    ser = ''
    def __init__(self):
        pass

    def Cancel_Timer(self):
        try:
            self.timer.cancel()
        except Exception as ex:
            template = "ct: An exception of type {0} occured. Arguments:\n{1!r}"
            message = template.format(type(ex).__name__, ex.args)
            print(message)

    def OpenSerial(self, COM, Baud, Parity, sBits, dBits, Timeout):
        try:
            self.ser = Serial(port=COM, baudrate=Baud, parity=Parity,
                         stopbits=sBits, bytesize=dBits, timeout=Timeout)
        except Exception as ex:
            template = "op: An exception of type {0} occured. Arguments:\n{1!r}"
            message = template.format(type(ex).__name__, ex.args)
            print(message)

    def SendSerial(self, data):   
        try:
            if self.ser.is_open:
                s = str(data)
                chars = []
                for c in s:
                    chars.append(ord(c))
                    chars = list(map(int, chars))
                self.ser.write(chars)
                self.ser.flush() 
        except Exception as ex:
            template = "ss: An exception of type {0} occured. Arguments:\n{1!r}"
            message = template.format(type(ex).__name__, ex.args)
            print(message)

    def ReadSerial(self, tmr, period):
        try:
            if self.ser.inWaiting() > 0:
                __stb = self.ser.read(self.ser.inWaiting())
                self.buffer += __stb
        except Exception as ex:
            template = "rs: An exception of type {0} occured. Arguments:\n{1!r}"
            message = template.format(type(ex).__name__, ex.args)
            print(message)
        if not tmr:
            return
        self.timer = threading.Timer(period, self.ReadSerial, [ True, period])
        self.timer.start()
        return


mySer = myser()
mySer.OpenSerial('COM7', 19200, 'N', 1, 8, 0)
data = '010111010001'
mySer.SendSerial(data)

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您可以使用package struct将数据转换为二进制，然后将其与PySerial一起发送感谢您的回答！我可以使用pyserial一次发送12位吗？@scholi