在Python3中重写十六进制？

我有以下课程：

from __future__ import print_function

class Proxy(object):
    __slots__ = ['_value']

    def __init__(self, obj):
        self._value = obj

    def __hex__(self):
        return hex(self._value)

print(hex(42))
print(hex(Proxy(42)))

在Python2.7中，这将打印

(py2.7) c:\hextest> python hextest.py
0x2a
0x2a

但在Py3.8中，这引发了一个例外：

(py3.8) c:\hextest> python hextest.py
0x2a
Traceback (most recent call last):
  File "hextest.py", line 14, in <module>
    print(hex(Proxy(42)))
TypeError: 'Proxy' object cannot be interpreted as an integer

（py3.8）c:\hextest>python hextest.py
0x2a
回溯（最近一次呼叫最后一次）：
文件“hextest.py”，第14行，在
打印（十六进制（代理（42）））
TypeError:“代理”对象不能解释为整数

我需要实现什么才能将代理解释为整数？

（其他Python 3.0计划）的目标之一是：

[删除]

\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

要实现这一点，您需要实现
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu索引
，可能如下所示：

def __index__(self):
    # or self._value if you know _value is an integer already
    return operator.index(self._value)

您可以看到更改此行为的提交：

（其他Python 3.0计划）的目标之一是：

[删除]
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

要实现这一点，您需要实现
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu索引
，可能如下所示：

def __index__(self):
    # or self._value if you know _value is an integer already
    return operator.index(self._value)

您可以看到更改此行为的提交：

如中所示，您应该定义
\uuuuuuu索引（）
。如中所示，您应该定义
\uuuuuu索引（）
。