Python 为什么ResultSet对象没有“find”属性？

我正试图把维基百科头版上维基百科其他部分的内容删掉。但是，我遇到错误ResultSet对象没有属性“find”。我的代码出了什么问题？如何使其工作

import requests
from bs4 import BeautifulSoup
url = 'https://en.wikipedia.org/'
response = requests.get(url)
soup = BeautifulSoup(response.text, 'lxml' )
otherAreasContainer = soup.find_all('div', class_='mp-bordered')
otherAreasContainerTexts = otherAreasContainer.find_all('li')
for otherAreasContainerText in otherAreasContainerTexts:
    print(otherAreasContainerText.text)

---

运行我得到的代码

Traceback (most recent call last):
  File "h.py", line 7, in <module>
    otherAreasContainerTexts = otherAreasContainer.find_all('li')
  File "/home/td/anaconda3/lib/python3.7/site-packages/bs4/element.py", line 1620, in __getattr__
    "ResultSet object has no attribute '%s'. You're probably treating a list of items like a single item. Did you call find_all() when you meant to call find()?" % key
AttributeError: ResultSet object has no attribute 'find_all'. You're probably treating a list of items like a single item. Did you call find_all() when you meant to call find()?

在代码中，OtherAreaContainer的类型为ResultSet，而ResultSet没有.find_all方法

要从Wikipedia的其他区域下选择all，可以使用CSS选择器h2:Containes Wikipedia的其他区域+div li

例如：

import requests
from bs4 import BeautifulSoup


url = 'https://en.wikipedia.org/'
soup = BeautifulSoup(requests.get(url).content, 'lxml')

for li in soup.select('h2:contains("Other areas of Wikipedia") + div li'):
    print(li.text)

印刷品：

Community portal – Bulletin board, projects, resources and activities covering a wide range of Wikipedia areas.
Help desk – Ask questions about using Wikipedia.
Local embassy – For Wikipedia-related communication in languages other than English.
Reference desk – Serving as virtual librarians, Wikipedia volunteers tackle your questions on a wide range of subjects.
Site news – Announcements, updates, articles and press releases on Wikipedia and the Wikimedia Foundation.
Village pump – For discussions about Wikipedia itself, including areas for technical issues and policies.

更多信息。

查找所有内容的结果是一个列表，并且列表没有“查找”或“查找所有内容”属性，您必须迭代otherAreasContainer，然后对其调用“查找所有内容”方法，如下所示：

import requests
from bs4 import BeautifulSoup


url = 'https://en.wikipedia.org/'
response = requests.get(url)
soup = BeautifulSoup(response.text, 'lxml')
otherAreasContainer = soup.find_all('div', class_='mp-bordered')

for other in otherAreasContainer:
    otherAreasContainerTexts = other.find_all('li')

    for otherAreasContainerText in otherAreasContainerTexts:
        print(otherAreasContainerText.text)

---

完整的堆栈跟踪将有所帮助。我们看不到是哪个行号导致了错误。请发布完整的回溯，以便我们可以看到导致问题的extact错误文本和行。可能find_all返回一个列表或迭代器，而您正在尝试对列表对象执行find_all？谢谢，但我从主页的其他部分获得了元素，如艺术传记地理历史数学科学社会技术等所有门户网站​“列表未找到属性”是什么意思？谢谢。列表是其他语言中类似python的数组中的数据类型之一，列表本身支持append not find或find_all等方法，这些方法仅适用于bs4对象。

import requests
from bs4 import BeautifulSoup


url = 'https://en.wikipedia.org/'
response = requests.get(url)
soup = BeautifulSoup(response.text, 'lxml')
otherAreasContainer = soup.find_all('div', class_='mp-bordered')

for other in otherAreasContainer:
    otherAreasContainerTexts = other.find_all('li')

    for otherAreasContainerText in otherAreasContainerTexts:
        print(otherAreasContainerText.text)