Python-KeyError:'；x'；

这是我的号码2文本代码：

num = raw_input "insert an int"
p = len(num) 
if p == 1:
    print numbers[num]
if p == 2:
    print tens[num[0]] + numbers_teeens[num[1]]
if p == 3:
    print numbers_hundreds[num[0]] + tens[num[1]] + numbers_teeens[num[2]]
if p == 4:
print numbers_thousands[num[0]]+ numbers_hundreds[num[1]] + tens[num[2]] + numbers_teeens[num[3]]
if p == 5:
print numbers_ten_thousands[num[0]] + numbers_thousands[num[1]]+ numbers_hundreds[num[2]] + tens[num[3]] + numbers_teeens[num[4]]
if p == 6:
print numbers_hundred_thousands[num[0]] + numbers_ten_thousands[num[1]] + numbers_thousands[num[2]]+ numbers_hundreds[num[3]] + tens[num[4]] + numbers_teeens[num[5]]

这些是我的字典：

numbers = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine'}
tens = {1: 'Ten', 2: 'Twenty', 3: 'Thirty', 4: 'Forty', 5: 'fifty', 6: 'Sixty', 7: 'Seventy', 8: 'Eighty', 9: 'Ninety'}
numbers_teens = {1: 'Eleven', 2: 'Twelve', 3: 'Thirteen', 4: 'Fourteen', 5: 'Fifteen', 6: 'Sixteen', 7: 'Seventeen', 8: 'Eighteen', 9: 'Nineteen'}
numbers_teeens = {0 : '', 1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', 15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
numbers_hundreds = {}
numbers_thousands = {}
numbers_ten_thousands = {}
numbers_teen_thousands = {}
numbers_hundred_thousands = {}

#Creates lists
for k,v in numbers.items():
    numbers_hundreds.update({k: v.title() + ' Hundred'}) 
    numbers_thousands.update({k: v.title() + ' Thousand and'})  

for k1,v1 in tens.items():
    numbers_ten_thousands.update({k1: v1.title()})

for kt,vt in numbers_teens.items():
    numbers_teen_thousands.update({kt: vt.title() + ' Thousand'})

for k2,v2 in numbers_hundreds.items():
    numbers_hundred_thousands.update({k2: v2.title() + ' Thousand'}) 

例如，如果我的输入是

32

。我收到此错误

keyrerror:'2'

我看到了一些其他的帖子，但它们只是关于

KeyError:x

（没有

'

），而那些确实有

'

，只是因为有人忘了在dict中输入

x

---

谢谢大家!

请注意，错误消息说缺少的键是

'2'

，换句话说，是一个字符串。您将整数作为键，如

2

。您可以首先将键创建为字符串，也可以将字符串数据转换为整数进行查找。

请注意，错误消息说缺少的键是

'2'

，换句话说，是字符串。您将整数作为键，如

2

。您可以首先将键创建为字符串，也可以将字符串数据转换为整数进行查找。

它的意思是keyrerror:'2'。 我想你搞错了。 您的号码2文本代码错误。 而不是'TEN[NUM（0）]考虑“<强> TEN[INT]（STR（num）[0 ] ] < <强> >/p> 因此，如果你把这两个文本放在一起，你会得到：

numbers = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7:           'Seven', 8: 'Eight', 9: 'Nine'}
tens = {1: 'Ten', 2: 'Twenty', 3: 'Thirty', 4: 'Forty', 5: 'fifty', 6: 'Sixty', 7: 'Seventy', 8: 'Eighty', 9: 'Ninety'}
numbers_teens = {1: 'Eleven', 2: 'Twelve', 3: 'Thirteen', 4: 'Fourteen', 5: 'Fifteen', 6: 'Sixteen', 7: 'Seventeen', 8: 'Eighteen', 9: 'Nineteen'}
numbers_teeens = {0 : '', 1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', 15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
numbers_hundreds = {}
numbers_thousands = {}
numbers_ten_thousands = {}
numbers_teen_thousands = {}
numbers_hundred_thousands = {}

#Creates lists
for k,v in numbers.items():
    numbers_hundreds.update({k: v.title() + ' Hundred'}) 
    numbers_thousands.update({k: v.title() + ' Thousand and'})  

for k1,v1 in tens.items():
    numbers_ten_thousands.update({k1: v1.title()})

for kt,vt in numbers_teens.items():
    numbers_teen_thousands.update({kt: vt.title() + ' Thousand'})

for k2,v2 in numbers_hundreds.items():
    numbers_hundred_thousands.update({k2: v2.title() + ' Thousand'})

num = raw_input "insert an int"
p = len(num) 
if p == 1:
    print int(numbers[int(str(num))]
if p == 2:
    print tens[int(str(int(str(num)))[0])] + numbers_teeens[int(str(num))[1]]
if p == 3:
    print numbers_hundreds[int(str(num))[0]] + tens[int(str(num))[1]] + numbers_teeens[int(str(num))[2]]
if p == 4:
    print numbers_thousands[int(str(num))[0]]+ numbers_hundreds[int(str(num))[1]] + tens[int(str(num))[2]] + numbers_teeens[int(str(num))[3]]
if p == 5:
    print numbers_ten_thousands[int(str(num))[0]] + numbers_thousands[int(str(num))[1]]+ numbers_hundreds[int(str(num))[2]] + tens[int(str(num))[3]] + numbers_teeens[int(str(num))[4]]
if p == 6:
    print numbers_hundred_thousands[int(str(num))[0]] + numbers_ten_thousands[int(str(num))[1]] + numbers_thousands[int(str(num))[2]]+ numbers_hundreds[int(str(num))[3]] + tens[int(str(num))[4]] + numbers_teeens[int(str(num))[5]]

它说的是KeyError:'2'。 我想你搞错了。 您的号码2文本代码错误。 而不是'TEN[NUM（0）]考虑“<强> TEN[INT]（STR（num）[0 ] ] < <强> >/p> 因此，如果你把这两个文本放在一起，你会得到：

numbers = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7:           'Seven', 8: 'Eight', 9: 'Nine'}
tens = {1: 'Ten', 2: 'Twenty', 3: 'Thirty', 4: 'Forty', 5: 'fifty', 6: 'Sixty', 7: 'Seventy', 8: 'Eighty', 9: 'Ninety'}
numbers_teens = {1: 'Eleven', 2: 'Twelve', 3: 'Thirteen', 4: 'Fourteen', 5: 'Fifteen', 6: 'Sixteen', 7: 'Seventeen', 8: 'Eighteen', 9: 'Nineteen'}
numbers_teeens = {0 : '', 1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', 15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
numbers_hundreds = {}
numbers_thousands = {}
numbers_ten_thousands = {}
numbers_teen_thousands = {}
numbers_hundred_thousands = {}

#Creates lists
for k,v in numbers.items():
    numbers_hundreds.update({k: v.title() + ' Hundred'}) 
    numbers_thousands.update({k: v.title() + ' Thousand and'})  

for k1,v1 in tens.items():
    numbers_ten_thousands.update({k1: v1.title()})

for kt,vt in numbers_teens.items():
    numbers_teen_thousands.update({kt: vt.title() + ' Thousand'})

for k2,v2 in numbers_hundreds.items():
    numbers_hundred_thousands.update({k2: v2.title() + ' Thousand'})

num = raw_input "insert an int"
p = len(num) 
if p == 1:
    print int(numbers[int(str(num))]
if p == 2:
    print tens[int(str(int(str(num)))[0])] + numbers_teeens[int(str(num))[1]]
if p == 3:
    print numbers_hundreds[int(str(num))[0]] + tens[int(str(num))[1]] + numbers_teeens[int(str(num))[2]]
if p == 4:
    print numbers_thousands[int(str(num))[0]]+ numbers_hundreds[int(str(num))[1]] + tens[int(str(num))[2]] + numbers_teeens[int(str(num))[3]]
if p == 5:
    print numbers_ten_thousands[int(str(num))[0]] + numbers_thousands[int(str(num))[1]]+ numbers_hundreds[int(str(num))[2]] + tens[int(str(num))[3]] + numbers_teeens[int(str(num))[4]]
if p == 6:
    print numbers_hundred_thousands[int(str(num))[0]] + numbers_ten_thousands[int(str(num))[1]] + numbers_thousands[int(str(num))[2]]+ numbers_hundreds[int(str(num))[3]] + tens[int(str(num))[4]] + numbers_teeens[int(str(num))[5]]

---

我做了

num\u I=int（num）

，但当我试图输入

34

时，它告诉我

TypeError:“int”对象没有属性“\uu getitem\uuuuu”

，然后你没有做

int（num）

，你做了

int[num]

（我想）.而且我知道我仍然没有做

p==3

之后的所有事情。这不是一个聊天的好地方。如果num是int，则不能执行

num[i]

。我的代码中没有

num[i]

。。。我只是在问：我如何修复

TypeError:“int”对象没有属性“\uu getitem\uuuuu”

我做了

num\u I=int（num）

，但当我试图输入

34

时，它告诉我

TypeError:“int”对象没有属性“\uu getitem\uuuuuuuu”

，然后你没有做

int（num）

，你做了

int[num]

（我想）.而且我知道我仍然没有做

p==3

之后的所有事情。这不是一个聊天的好地方。如果num是int，则不能执行

num[i]

。我的代码中没有

num[i]

。。。我只是问：如何修复

TypeError:'int'对象没有属性'\uu getitem'