元组索引超出范围？python 3.4.2

我正在用python创建一个csv文件测验，在测验结束时看到总结之前一切都很好

percentage = (correctScore * 100) / 20

print("Alright now, lets see how you did... ")
time.sleep(2)
if correctScore == 20:
    print("Excellent work there, (yourNameIs), you scored 100%. ")
elif correctScore >= 11 <= 19:
    print("Well done", yourNameIs, "you passed. You scored", percentage,"%. You got {} question(s) wrong".format(len(incorrect)))
    for question, user_answer in incorrect:
        print("Q{}: {}".format(data[question][0]))
        print("\tYou answered {}. The correct answer is {}".format(user_answer, data[question][5]))
elif correctScore >= 5 <= 10:
    print("Good effort", yourNameIs, "you scored", percentage,"%. You got {} question(s) wrong".format(len(incorrect)))
    for question, user_answer in incorrect:
        print("Q{}: {}".format(data[question][0]))
        print("\tYou answered {}. The correct answer is {}".format(user_answer, data[question][5]))
else:
    print("You need to try harder next time", yourNameIs, "you scored", percentage,"%. You got {} question(s) wrong".format(len(incorrect)))
    for question, user_answer in incorrect:
        print("Q{}: {}".format(data[question][0]))
        print("\tYou answered {}. The correct answer is {}".format(user_answer, data[question][5]))

有什么想法吗

correctScore = 0 
incorrect = [] 
question = data[recordnum-1][0] 
a = data[recordnum-1][1] 
b = data[recordnum-1][2] 
c = data[recordnum-1][3] 
d = data[recordnum-1][4] 
answer = data[recordnum-1][5] –

---

在格式字符串中使用两个

{}

，但只传递一个arg，python需要两个参数进行格式化，因此将

索引器：元组索引超出范围

：

print("Q{0}: {1}".format(data[question][0]))  
        ^^    ^^

如果

数据[问题]

有两个元素，您可以使用

*

解包：

print("Q{0}: {1}".format(*data[question]))

---

无论哪种方式，您都需要通过两个参数。

1。请告诉我们

数据

在哪里分配，以及分配的代码。2.给我一个输入数据格式的例子。不仅仅是csv，而是一个条目的外观like@Vincenzzochi很抱歉下面是我得到的更正分数=0不正确=[]myFile=open（“questions.csv”，“r”）#打开csv文件并将其存储在数组myFile lines=myFile.readlines（）#将csv文件的行读取到变量players recordnum=1 random中。shuffle（lines）data=[p.strip（）.split（“，”）表示p in line]

question

也是一个数字，还是一个字符串？我们不想发送那个^。correctScore=0不正确=[]问题=数据[recordnum-1][0]a=数据[recordnum-1][1]b=数据[recordnum-1][2]c=数据[recordnum-1][3]d=数据[recordnum-1][4]答案=数据[recordnum-1][5]将此代码包含在问题中。

print("Q{0}: {1}".format(*data[question]))