Python 找出所有方法将列表分为三个部分

正如标题所说，我如何找到将一个列表划分为三个列表的所有方法？例如，1,2,3将返回

[1, 2, 3]
[1] [2] [3]
[1, 2] [3] [ ]
[1] [2, 3] [ ]
[1, 3] [2] [ ]

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我试过很多东西，但似乎都不懂。谢谢

您可以使用lib

itertools

import itertools

my_list = [1, 2, 3]

for i in range(len(my_list)):
    print(list(itertools.combinations(my_list, i + 1)))

哪个输出

[(1,), (2,), (3,)]
[(1, 2), (1, 3), (2, 3)]
[(1, 2, 3)]

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现在，您可以添加每个列表的长度，并添加缺少的空列表（以完成3个列表），瞧，您有了您的结果。

下面是一个可能的解决方案：

import itertools

# your input data list
a = [1, 2, 3]

# util function to convert list of tuples to list of list
f = lambda x: [list(i) if isinstance(i, tuple) else i for i in x]

# list1 is all combinations of sublists having length = 1,2,..length_of_a from input list `a` and empty list [] 
list1 = []
for i in range(1, len(a)+1):
    list1.extend(itertools.combinations(a, i))
list1.extend([()]*(len(a)-1))

# list2 is all combinations of sublists having length = length_of_a from the list1
list2 = list(set(itertools.combinations(list1, len(a))))

#  filtering out and converting list of tuples for the final results
results = [f(i) for i in list2 if sum(itertools.chain(*i)) == sum(a) and set(itertools.chain(*i)) == set(a)]
results.append(a)

# print out the results
for r in results:
    print(r)

产出：

[[1,2,3]，[]，[]

[3]，[1,2]，]

[1]、[2]、[3]]

[2]，[1,3]，]

[1]，[2,3]，]

---

[1,2,3]

应该[1,2,3][]也是一个答案吗？@wkzhu应该是我的错，这回答了你的问题吗？