Python帮助:gmplot中的路径

Python帮助:gmplot中的路径,python,path,polygon,Python,Path,Polygon,我找不到任何关于在gmplot中使用路径的文档。我提出了这段代码,虽然很接近,但它连接了所有的行,并用颜色填充了它——我不希望这样 我只想要这样一条路径: 但是,我得到的是: 这是我的密码: pathlon = -117.2974695,-117.2980671,-117.2984607,-117.2979182,-117.2974082,-117.2966604,-117.2977518,-117.2987498,-117.2981491,-117.297708,-117.2972804,

我找不到任何关于在gmplot中使用路径的文档。我提出了这段代码,虽然很接近,但它连接了所有的行,并用颜色填充了它——我不希望这样

我只想要这样一条路径:

但是,我得到的是:

这是我的密码:

pathlon = -117.2974695,-117.2980671,-117.2984607,-117.2979182,-117.2974082,-117.2966604,-117.2977518,-117.2987498,-117.2981491,-117.297708,-117.2972804,-117.2965301,-117.2979485,-117.2975028,-117.2980506,-117.2982983,-117.2976609,-117.2970861,-117.2969908,-117.2981731,-117.2987695,-117.2981146,-117.2976909,-117.2969674,-117.2969299,-117.298394
pathlat = 33.27172039,33.27197757,33.27217535,33.27225324,33.27218351,33.27233921,33.27242614,33.27248971,33.27268346,33.27265944,33.27263664,33.27279608,33.27281652,33.27194103,33.27176546,33.27224514,33.27222714,33.27208829,33.27237357,33.27243373,33.27262189,33.27268296,33.27265933,33.27262125,33.27282274,33.27283925

gmap = gmplot.GoogleMapPlotter(pathlat[0],pathlon[0],18)

gmap.polygon(pathlat,pathlon,edge_color="cyan", edge_width=5, face_color=None, face_alpha=None, clickable = False)

gmap.draw('map.html')
希望有人能给我指出正确的方向


提前谢谢

因为您使用的是多边形,所以这是预期的结果。你应该使用绘图法

请参阅以下部分

pathlon = -117.2974695,-117.2980671,-117.2984607,-117.2979182,-117.2974082,-117.2966604,-117.2977518,-117.2987498,-117.2981491,-117.297708,-117.2972804,-117.2965301,-117.2979485,-117.2975028,-117.2980506,-117.2982983,-117.2976609,-117.2970861,-117.2969908,-117.2981731,-117.2987695,-117.2981146,-117.2976909,-117.2969674,-117.2969299,-117.298394
pathlat = 33.27172039,33.27197757,33.27217535,33.27225324,33.27218351,33.27233921,33.27242614,33.27248971,33.27268346,33.27265944,33.27263664,33.27279608,33.27281652,33.27194103,33.27176546,33.27224514,33.27222714,33.27208829,33.27237357,33.27243373,33.27262189,33.27268296,33.27265933,33.27262125,33.27282274,33.27283925

gmap = gmplot.GoogleMapPlotter(pathlat[0],pathlon[0],18)

gmap.plot(pathlat,pathlon,'cornflowerblue', edge_width=10)

gmap.draw('map.html')

啊哈!这正是我所需要的。谢谢你,努里塞尔库克!我喜欢这个论坛。