使用Python提取字段

我正在寻找帮助，以提取一个特定的领域

这里是一个例子，我无法根据字段编号进行拆分和剪切，因为编号可能会因内容更改而更改

示例1

[["cn","Phone",1,"","LI(\"\")","0","19%","",""],["OS_DisplayName","Display Name",1,"","LI(\"\")","1,0","19%","",""],["OS_ProductPackage","Product Package",1,"","CO(\"\",\"REQ;1_BASIC!OS!TRV;2_Messaging!OS!OEM;3_Extended!OS!EAC;4_Enhanced!OS!APO;5_Analog Port!OS!CCA;6_Contact Center Agent\",\"\",\";\",\"\",\"\")","2,0","19%","",""],["sn","Last name",1,"","LI(\"\")","3,0","12%","",""],["givenName","First name",1,"","LI(\"\")","4,0","12%","",""],["OS_SiteCode","Site Code",1,"","LI(\"\")","5,0","19%","",""]],[["917845678923","Backup","OEM","917845678923","","CNdd_RD_91784567","","cn=917845678923,cn=Subscribers,cn=np_CNdd_RnD_WangJing,cn=IPC_APAC_1_01,cn=DN,cn=Resources,cn=Users,cn=OS"]],

输出应该是

cn=917845678923,cn=Subscribers,cn=np_CNdd_RnD_WangJing,cn=IPC_APAC_1_01,cn=DN,cn=Resources,cn=Users,cn=OS 

示例2

[["cn","Phone",1,"","LI(\"\")","0","19%","",""],["OS_DisplayName","Display Name",1,"","LI(\"\")","1,0","19%","",""],["OS_ProductPackage","Product Package",1,"","CO(\"\",\"REQ;1_BASIC!OS!TRV;2_Messaging!OS!OEM;3_Extended!OS!EAC;4_Enhanced!OS!APO;5_Analog Port!OS!CCA;6_Contact Center Agent\",\"\",\";\",\"\",\"\")","2,0","19%","",""],["sn","Last name",1,"","LI(\"\")","3,0","12%","",""],["givenName","First name",1,"","LI(\"\")","4,0","12%","",""],["OS_SiteCode","Site Code",1,"","LI(\"\")","5,0","19%","",""]],[["868694755000","Yaeng Danning","EAC","Yaeng","Dainning","CNdd_DT_86869475","","cn=868694755000,cn=Subscribers,cn=np_CNdd_DN,cn=IPC_APAC_1_01,cn=DN,cn=Resources,cn=Users,cn=OS"]],

输出应为

cn=868694755000,cn=Subscribers,cn=np_CNdd_DN,cn=IPC_APAC_1_01,cn=DN,cn=Resources,cn=Users,cn=OS

有人能帮我吗

我尝试了下面的代码，但由于字段号更改，我无法使用常量字段号（e[8]）

    e = line3.split('","","')
    print "e"
    print e
    e = e[8].replace('"]],','').replace('","','').strip()
    print "e:" ,e

---

如果保证

cn

字段是最后一个字段，则可以执行以下操作：

cnFields = array [-1][-1]

然后按照您认为合适的方式对其进行解析

---

否则，您需要遍历2d数组，直到找到以

cn=

开头的字符串

如果保证

cn

字段是最后一个字段，您可以执行以下操作：

cnFields = array [-1][-1]

然后按照您认为合适的方式对其进行解析

---

否则，您需要遍历2d数组，直到找到以

cn=

开头的字符串

您可以将列表展平，然后在其中搜索

myList = (['one', 'two', ['cn=blahblah', 4, [5],['hi']], [6, [[[7, 'hello']]]]])

def flatten(container):
  for i in container:
    if isinstance(i, (list,tuple)):
      for j in flatten(i):
        yield j
    else:
      yield i

flattenedList = list(flatten(myList))

for x in flattenedList:
  if str(x).startswith('cn='):
    print(x)

---

您可以将列表展平，然后在其中搜索

myList = (['one', 'two', ['cn=blahblah', 4, [5],['hi']], [6, [[[7, 'hello']]]]])

def flatten(container):
  for i in container:
    if isinstance(i, (list,tuple)):
      for j in flatten(i):
        yield j
    else:
      yield i

flattenedList = list(flatten(myList))

for x in flattenedList:
  if str(x).startswith('cn='):
    print(x)

---

e=line3.split（“，”，“）

print e

e=e[8]。替换（“]”、“，”）。替换（“，”）。strip（）

print“e:“，e

请编辑您的帖子-注释不是放置代码的正确位置。我尝试了此操作，现在它正在工作。我无法使用常量字段编号，您可以看到字段编号正在更改。

e=line3.拆分（“，”，“，”）

打印e

e=e[8]。替换（“，”，”）。替换（“，”，“，”）。带（）“，e

请编辑您的帖子-注释不是放置代码的正确位置。我尝试了此方法，现在它正在工作。我不能使用常量字段编号，您可以看到字段编号正在更改。

>b=s[-1][-1]

>>sd=b[+7]

>打印sd

这对我有用吗我们可以在单行中使用它[-1][1]

>sd=b[+7]

>print sd
这对我有用吗？我们可以用单行吗？请给我一个例子，我给你写了工作代码…你应该把你的列表放在名为“myList”的变量中，它将被展平为一个简单的一维列表，您可以用一个简单的循环来解析。但是，当我尝试下面的展平列表打印链接时，
['、['、'、'、'c'、'n'、'、'P'、'h'、'o'、'n'、'e'、'、'1'、'、'、'、'、'、'L'、'i'、'（'、'、'、'\\'、'",","0",","0",","0",","0",","0","","0","",""",""",""0",",",",",",",",",","","“，
用括号将列表括起来定义它…例如：myList=（[[“cn”，“Phone”，1，“，………=”用户，cn=OS“]）你能给我一个例子吗？我给你写了工作代码…你应该把列表放在名为“myList”的变量中，它将被展平为一个简单的一维列表，您可以用一个简单的循环来解析它。但是当我尝试我的展平列表打印链接时，它位于
['、['、'、'、'c'、'n'、'、'、'P'、'h'、'o'、'n'、'e'、'、'、'、'、'、'1'、'、'、'、'、'、'、'、'、'、'、'、'、'、'、'L'、'（'、'、'、'、'、'、'、'、'、'、'、'、'、'（'、'、'、'、'、'、'、'、'、'、'、'、'、'、'、'、'、",","0",","0",","0",","0",","0","","0","",""",""",""0",",",",",",",",",","","“，
将列表括在括号中以定义它…例如：myList=（[[“cn”，“Phone”，1，“，………=用户，cn=OS”]）