我需要使用python json解析将我的2个列表组合成另一个1

我有2个json文件： rooms.json students.json 我需要通过students.json中的room id和属性room将它们划分到另一个列表中 rooms.json：

[
{
    "id": 0,
    "name": "Room #0"
},
{
    "id": 1,
    "name": "Room #1"
},
{
    "id": 2,
    "name": "Room #2"
}
]

students.json：

[
{
    "id": 0,
    "name": "Ryan Keller",
    "room": 1
},
{
    "id": 1,
    "name": "Brooke Ferrell",
    "room": 1
},
{
    "id": 2,
    "name": "Travis Tran",
    "room": 0
}
]

我在用这个：

import json

rooms_file = 'rooms.json'
with open(rooms_file) as f:
    rooms_new = json.load(f)
students_file = 'students.json'
with open(students_file) as file:
    student_new = json.load(file)

relocation_file = 'relocation.json'


for i in students_file:
    if "room" == id in rooms_file:
        with open(relocation_file) as fl:
            relocation_new = json.dump(relocation_file,'w')

我做错了什么，请帮帮我。 它不返回任何内容，但可能应该创建一个文件“relocation.json” 其中包含如下列表：

 [
{
  "id": 0,
  "name": "Room #0"
  "name": "Travis Tran",
  },
{
  "id": 1,
  "name": "Room #1"
  "name": "Brooke Ferrell",
  "name": "Ryan Keller",
  },

]

---

你能试试下面的代码吗？我想你期望的答案不应该有相同的键名，所以我将其重命名为

学生名

，作为键（如果需要，你可以将

名称

更改为

房间名

）。我希望这对你也很好

import json

with open('files/rooms.json') as f:
    room_list = json.load(f)

with open('files/students.json') as file:
    student_list = json.load(file)


relocation_list = []

for student_dict in student_list:
    for room_dict in room_list:
        new_dict = {}
        if student_dict['room'] == room_dict['id']:
            new_dict["student_name"] = student_dict['name']
            new_dict.update(room_dict)
            relocation_list.append(new_dict)

with open('relocation.json', 'w') as f:
    f.write(str(relocation_list))

print(relocation_list)

输出：

[{'student_name': 'Ryan Keller', 'id': 2, 'name': 'Room #2'}, {'student_name': 'Brooke Ferrell', 'id': 1, 'name': 'Room #1'}, {'student_name': 'Travis Tran', 'id': 0, 'name': 'Room #0'}]

使用列出全面的方式：

import json

with open('files/rooms.json') as f:
    room_list = json.load(f)

with open('files/students.json') as file:
    student_list = json.load(file)

print([{**room_dict, "student_name": student_dict['name']} for room_dict in room_list for student_dict in student_list if student_dict['room'] == room_dict['id']])
# output
# [{'id': 0, 'name': 'Room #0', 'student_name': 'Travis Tran'}, {'id': 1, 'name': 'Room #1', 'student_name': 'Brooke Ferrell'}, {'id': 2, 'name': 'Room #2', 'student_name': 'Ryan Keller'}]

---

编辑 对于评论中提到的新要求

• 避免在

  重新定位\u列表

  中重复ID-这里我们将

  学生名

  的值合并到学生列表中
• 按值对dict列表进行排序-Ref：检查此项还有许多其他方法

---

您的输出似乎与您尝试执行的操作不匹配。Ryan Keller在顶部的房间值为2，但在输出中的房间值为1。这是需要的吗？请清理您的输出文件，或者更清楚地了解您想要的逻辑。抱歉，现在它需要尝试，并且它输出以下内容：[{'id'：5，'name'：'Room#5'，'student#name'：'Cassandra Wilson'}，{'id'：5，'name'：'Room#5'，'student#name'：'Cassandra Wilson'}，我需要为10000名学生和1000个房间做这个，但是现在我尝试了10名学生和10个房间，尝试你的代码更简单很好，谢谢你的帮助，但效果不是很好）很抱歉，你能现在检查一下吗？我已经更正了代码。谢谢你，你帮了我这么多，我能请你帮我把它按1 t排序吗例如，离开3号房间的学生在一本字典中，比如[{'student_name'：'Ryan Keller'，'student_name'：'Brooke Ferrell'，'id'：0，'name'：'room#0'}当然，所以你的第一个请求是你想要最终结果（

重新定位列表

）要按房间编号排序吗？第二部分我不太明白，你能不能用另一个例子再解释一遍，这样我现在就可以快速尝试了？

import json

with open('files/rooms.json') as f:
    room_list = json.load(f)

with open('files/students.json') as file:
    student_list = json.load(file)


relocation_list = []


# We arent considering about duplicate item as it is created by same loop
def check_room_id_in_relocation_list(id_to_check):
    is_exist, index, item = False, None, {}
    for index, item in enumerate(relocation_list):
        if id_to_check == item['id']:
            is_exist, index, item = True, index, item
    return is_exist, index, item


for student_dict in student_list:
    for room_dict in room_list:
        new_dict = {}
        if student_dict['room'] == room_dict['id']:
            is_room_exist, index, item = check_room_id_in_relocation_list(room_dict['id'])
            if is_room_exist:
                # To merge same ids
                # since it already exist so update list's item with new student_name
                # instead of new key we are assigning list of names to key "student_name" to 
                relocation_list[index]['student_name'] = [relocation_list[index]['student_name'], 'new nameeeee']
            else:
                new_dict["student_name"] = student_dict['name']
                new_dict.update(room_dict)
                relocation_list.append(new_dict)

print("student list:", student_list)
print("room list: ", room_list)
print("relocation_list:", sorted(relocation_list, key=lambda k: k['id']))
with open('relocation.json', 'w') as f:
    f.write(str(sorted(relocation_list, key=lambda k: k['id'])))

# output
# student list: [{'id': 0, 'name': 'Ryan Keller', 'room': 2}, {'id': 1, 'name': 'Brooke Ferrell', 'room': 1}, {'id': 2, 'name': 'Travis Tran', 'room': 0}, {'id': 3, 'name': 'New User', 'room': 2}]
# room list:  [{'id': 0, 'name': 'Room #0'}, {'id': 1, 'name': 'Room #1'}, {'id': 2, 'name': 'Room #2'}]
# relocation_list: [{'student_name': ['Travis Tran', 'new nameeeee'], 'id': 0, 'name': 'Room #0'}, {'student_name': 'Brooke Ferrell', 'id': 1, 'name': 'Room #1'}, {'student_name': 'Ryan Keller', 'id': 2, 'name': 'Room #2'}]